Electronics Engineering

For a transistor to be in active region :

Base Emitter junction should be forward biased and Emitter collector junction should be reverse biased.

rf is a single tuned amplifier . Its functions are :-

1.improves selectivity ( i.e rejection of unwanted signal) , so that it prevents heterodyning which results in interference frequency.

2. improves image frequency rejection

3. improves sensitivity ( gain of amplifier )

4.improves coupling of receiver with antenna .

5. improves signal to noise ratio.

6. reradiation of local oscillator through receiver antenna is prevented

If the current in the wire increases, the magnetic field also increases.

250 nominal diameter, withstands of 16 bar pressure UPVC pipe,

Every multivibrators have two states:quasi stable and stable state.

quasi stable state are triggered state, when a trigger pulse is given the vibrator reaches this state.

For example,

Astable multivibrators have no triggers so,two stable states.

Monostable multivibrators have one trigger so,one stable and one quasi stable which is invoked by the trigger.Same for the Bistable in which two sates are invoked by two triggers.

Output of an Amplifier is given back to same Amplifiers input in out of phase. act as subtracter. if amplifiers output excess the some portion is given back to input and it reduces the original input. this makes original signal so small so that gives desired output. its of course close loop so by this manner this negative feedback stabilizes gain.

You can compare a power supply to a waterfall of energy.

The high of the waterfall is the output voltage, and the quantity of water in the river is the current intensity.

The power generate is a combination of the intensity and the voltage: P=UI (the effective power is the result of the multiplication of the voltage and the intensity).

That explain why higher the voltage is, less intensity is needed to have the same power.

It is the same in a waterfall, higher it is, less water you need to make a mill turning.

No world is a stage, and you cannot detect a helicopter unless you have the radar station (radar alone is not sufficient)

a long string of numbers

It depends on the turns ratio of the transformer.

If the two 5 ohm resistors were in series, then the current would be 1.2 amperes. If they were in parallel, then the current would be 4.8 amperes.

Ohm's Law: Current = Voltage divided by Resistance

RSeries = Summation1toN RN

RPARALLEL = 1 / Summation1toN (1 / RN)

the advantage of JK flip-flop compared to clocked SR flip

Yes, but why? The receiver at the tower could not decode it and would most likely filter any modulated signal.

The emitter resistor places limits on the required gain, and temperature stabilizes the transistor. Without it, gain is hFe, but that is variable, temperature dependent, and subject to thermal runaway. With it, gain is predictable (collector resistor divided by emitter resistor, though limited by hFe), and temperature stabilized (so long as both resistors have the same temperature coefficient, and so long as the hFe margin is maintained).

The 1N5408 is rated 3 amperes forward current and 1000 volt reverse voltage, with a 200 ampere peak surge current rating. The BY255 is rated 3 amperes forward current and 1300 volt reverse voltage, with a 100 amperes peak surge current rating.

The two diodes are comparable, but the 1N5408 has a higher transient rating.

Since it does not seem that you are talking about a power supply application, you can probably substitute the BY255 for a 1N5408. It depends on the circuit design, but most circuits (if properly designed) are over-rated so, again, it would probably work.

I would not use the BY255 in the power supply, however, due to the short term transient that comes from turning on the power. Again, circuit design prevails, and it might work even there, because inrush current will be limited by the inductance of the transformer and the dynamic resistance of the diode.

The time constant of an RL series circuit is calculated using the formular:

time constant=L/R

Power transformers can be used for power transformation. Voltage transformers are not suitable for high power applications.

0.7

The voltage across a silicon diode when it is forward biased should be greater than or equal (>=) 0.7volts.

ac power (alternating current)

it blocks dc power

Many people will say a capacitor can't pass current because they consider Electric current to be the flow of electrons but that's not necessarily the case. In a capacitor current is passed by the building up and dropping of an electric field. DC does not flow for long of course.

No because it has finite power therefore infinite energy => not an energy signal

because it is gcr not scr

depends on what you are conducting but generally a metal is a universal conductor. if it conducts electricity well then it will conduct heat well. some metals are better than others and you can figure this out by resistance values of the type of metal. more resistance makes it a less efficient conductor. insulators have very high resistance.

The time constant for an RL-circuit is equal to L/R. In this case, (0.002 H)/(200 ohm).

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