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Intel 8086 and 8088

The Intel 8086/8088 family of microprocessors is a 16 bit architecture on a 16 bit (8086) or an 8 bit (8088) bus. The 8088 was the processor in the original IBM PC, and has evolved into the most popular processor used today in PC's and servers.

1,056 Questions

What is the advantage of addressing mode in 8086 microprocessor?

The addressing modes in the 8086 microprocessor provide flexibility in accessing data by allowing various ways to specify the operands for instructions. This enables programmers to efficiently use memory by accessing data directly, indirectly, or using offsets, which can simplify code and reduce the number of instructions needed. Additionally, different addressing modes facilitate the manipulation of data structures, such as arrays and records, enhancing the overall versatility and power of the microprocessor.

What is the difference between shift and rotate instructions of 8086 microprocessor?

In the 8086 microprocessor, shift instructions move bits in a binary number to the left or right, effectively multiplying or dividing the value by powers of two. For example, a left shift (SHL) doubles the number, while a right shift (SHR) halves it. In contrast, rotate instructions (RCL, RCR, ROL, ROR) also move bits but they wrap around the bits that are shifted out, placing them back into the opposite end of the number. This means that while shift operations affect the value of the number, rotate operations preserve the overall bit pattern.

What is total amount of memory in a 16-bit address bus in units of K?

A 16-bit address bus can address (2^{16}) memory locations, which equals 65,536 locations. Since each location typically represents one byte, the total memory is 65,536 bytes. To convert this into kilobytes (K), divide by 1,024, resulting in 64 K. Thus, a 16-bit address bus can address a total of 64 Kbytes of memory.

Ip address are broken into 8 segments each segments consisting of 8 bits?

IP addresses are typically represented in two primary formats: IPv4 and IPv6. In IPv4, an address consists of four segments (octets) of 8 bits each, resulting in a total of 32 bits. Each segment can range from 0 to 255, allowing for over four billion unique addresses. In contrast, IPv6 uses eight groups of 16 bits, significantly increasing the number of available addresses to accommodate the growing number of devices on the internet.

What jmp instruction assembles if distance is 0020h bytes?

If the distance for a JMP instruction is 0020h bytes, it typically assembles to a short jump instruction (if the target is within a certain range) or a near jump instruction. In this case, a near jump would be used, which consists of the opcode followed by a 16-bit offset. The exact opcode will depend on the assembly language and architecture, but for x86, a near JMP could be represented as EB for a short jump or E9 followed by the relative address for a long jump.

What universal issue does wiglaf address in lines 745-772?

In lines 745-772 of "Beowulf," Wiglaf addresses the universal issue of loyalty and the responsibilities of leadership. He criticizes the other warriors for abandoning Beowulf in his time of need, emphasizing the importance of standing by one’s leader and the values of courage and commitment. This moment underscores the theme of honor in relationships and the consequences of failing to support those who uphold the community's safety and well-being. Wiglaf's speech serves as a reminder of the ethical obligations that bind individuals to one another, especially in moments of crisis.

What does the size of the address bus affect?

The size of the address bus affects the maximum amount of memory a computer can directly access. Specifically, it determines the number of unique memory addresses that can be generated, which is calculated as 2 raised to the power of the address bus size (in bits). For example, a 32-bit address bus can address up to 4 GB of memory, while a 64-bit address bus can theoretically access 16 exabytes. Thus, a larger address bus allows for greater memory capacity and can enhance overall system performance.

How did bread lines address the growing problems of unemployed?

Bread lines emerged during economic crises, such as the Great Depression, as a vital means to alleviate the suffering of the unemployed and impoverished. They provided free or low-cost food to those in dire need, helping to stave off hunger and malnutrition. By ensuring access to basic sustenance, bread lines not only addressed immediate food insecurity but also served as a crucial support system for communities grappling with widespread unemployment. Ultimately, they highlighted the need for larger social safety nets to support individuals during economic downturns.

What is the max memory capacity of 8086?

The maximum memory capacity of the 8086 microprocessor is 1 megabyte (MB). This limitation arises from its 20-bit address bus, which allows it to address up to 2^20 memory locations, equating to 1,048,576 bytes or 1 MB. The memory is organized into segments, with the segmentation scheme allowing for more efficient memory management within this address space.

What is functional pin diagram?

A functional pin diagram is a visual representation that illustrates the arrangement and function of pins or terminals on an integrated circuit (IC) or electronic component. Each pin is labeled to indicate its specific role, such as power supply, ground, input, output, or control signals. This diagram helps engineers and designers understand how to connect and utilize the component within a circuit, ensuring proper functionality and integration. It serves as a crucial reference during the design and troubleshooting processes.

How do you write a code to complement the corresponding bit in bxif AX contains 6complement the 6th bit of BX in assembly?

To complement the 6th bit of the BX register in assembly language, you can use the XOR instruction. First, create a mask that has the 6th bit set (binary 00100000, which is 0x20 in hexadecimal). Then, XOR the BX register with this mask to toggle the 6th bit. Here's an example in x86 assembly:

mov ax, <value>  ; Load AX with some value
xor bx, 0x20     ; Complement the 6th bit of BX

This will flip the 6th bit of BX without affecting the other bits.

Which register stores intrrupt and subroutine return address register in 8086?

In the 8086 microprocessor, the register that stores the interrupt and subroutine return address is the Instruction Pointer (IP) register. When an interrupt occurs or a subroutine is called, the current instruction address is pushed onto the stack, allowing the processor to return to that location after the interrupt or subroutine execution is complete. The IP register works in conjunction with the Code Segment (CS) register to determine the effective address of the next instruction to execute.

What do you mean by stack explain the push or pop operation?

A stack is a linear data structure that follows the Last In, First Out (LIFO) principle, meaning the last element added is the first one to be removed. The "push" operation adds an element to the top of the stack, while the "pop" operation removes the element from the top. Both operations are typically performed in constant time, O(1), making stacks efficient for various applications, such as function call management and expression evaluation in programming.

What addressing mode could be used to add the contents of a memory location to the contents of accumulator A?

To add the contents of a memory location to the contents of accumulator A, the direct addressing mode can be used. In this mode, the instruction specifies the actual memory address where the operand is located. The processor retrieves the value from that memory address and adds it directly to the contents of accumulator A. This method allows for straightforward access to the operand stored in memory.

Why sp is 8 bit long while PC and dptr are 16 bit longs in 8051?

In the 8051 microcontroller architecture, the stack pointer (SP) is 8 bits long because it directly addresses a limited range of memory locations within the internal RAM, specifically up to 256 bytes. In contrast, the program counter (PC) and data pointer (DPTR) are 16 bits long to accommodate larger address spaces; the PC can address up to 64KB of program memory, while the DPTR can address up to 64KB of external data memory. This distinction allows for efficient use of resources while maintaining compatibility with the architecture's requirements.

Is physical address changed?

A physical address can change for various reasons, such as relocation, changes in property ownership, or municipal reassignments of street names or numbers. If you are asking about a specific location, it's best to check with local authorities or online mapping services for the most current information. Otherwise, addresses can be updated and modified over time.

What is Indirect Mode?

Indirect Mode refers to a method of communication or interaction where the message is conveyed indirectly rather than explicitly. This can include using hints, suggestions, or non-verbal cues instead of straightforward language. It is often employed in contexts where direct confrontation might be inappropriate or when the speaker wants to maintain politeness or avoid offending the listener. Indirect Mode can also apply to various fields, such as finance or technology, where processes or actions are carried out through intermediary steps rather than direct means.

How does 8086 differentiate between an opcode and operand?

The 8086 microprocessor differentiates between an opcode and an operand primarily through the instruction format, where the opcode is always specified first, followed by the operands. The opcode indicates the operation to be performed, while the operands represent the data or addresses on which the operation will act. The instruction's length is variable, and the processor uses specific bits in the instruction to determine the types and sizes of operands, allowing it to interpret the instruction correctly. Additionally, the opcode itself can include information about the addressing mode, further aiding in the distinction between opcodes and operands.

How many wires are there on an address bus for modern cpu's?

The number of wires on an address bus for modern CPUs typically ranges from 32 to 64 bits, meaning there are usually 32 to 64 individual wires. This allows them to address anywhere from 4 GB (in a 32-bit system) to 16 EB (in a 64-bit system) of memory. Some specialized or high-performance processors may use wider address buses, but 32 and 64 bits are the most common in contemporary consumer CPUs.

What is hardware interrupt of 8085 microprocessor with vector interrupt?

In the 8085 microprocessor, a hardware interrupt is a signal from an external device that temporarily halts the CPU's current operations to allow the device to communicate with the processor. A vector interrupt specifically refers to an interrupt that has a predefined memory address (vector) associated with it, which the processor jumps to when servicing the interrupt. For instance, the 8085 has several hardware interrupts, such as INTR, RST 7.5, RST 6.5, and RST 5.5, each with its own unique vector address, allowing for efficient and organized handling of multiple interrupt sources. This mechanism enables real-time processing and responsiveness to external events in embedded systems.

What is the Difference of Address line 1 and Address line 2?

Address Line 1 typically includes the primary address information, such as the street number and name, for example, "123 Main St." Address Line 2 is used for additional address details that may be necessary, such as apartment numbers, suite numbers, or building names, like "Apt 4B" or "Building C." This format helps ensure that the full address is complete and accurate for delivery or location purposes.

Where 8086 microprocessors are used.......And even i want to know the applications of 8086..?

The 8086 microprocessor is primarily used in embedded systems, industrial automation, and control systems due to its simplicity and efficiency. It serves as a foundational component in early personal computers and is still utilized in educational settings for teaching computer architecture and assembly language programming. Additionally, it finds applications in legacy systems and hardware that require basic processing capabilities. Its architecture also paved the way for more advanced processors, influencing modern computing designs.

What is the maximum length of instruction in 8086?

In the 8086 microprocessor, the maximum length of an instruction is 6 bytes. This includes the opcode, any necessary prefixes, and operands. The architecture allows for complex addressing modes, which can contribute to the instruction length, but the limit remains at 6 bytes for any single instruction.

As a memory segment is 64k does it mean that 64k are the total addresses in a segment if 64K is the total addresses in a segment then what is the sizebytes of one segment 64k?

Yes, if a memory segment is 64K, it means there are 64K total addresses in that segment. Since 1K (kilobyte) equals 1024 bytes, a 64K segment would have a total size of 64 * 1024 bytes, which equals 65,536 bytes. Therefore, the size of one segment is 65,536 bytes.

What is the effective address generated by the following combinations if they are valid. If not give reason. Initially BX0x0100 SI0x0010 DI0x0001 BP0x0200 and SP0xFFFF a. bx-si b. bx-bp c. bx plus 10?

To calculate the effective addresses for the given combinations:

a. BX - SI: This results in 0x0100 - 0x0010 = 0x00F0, which is valid. b. BX - BP: This gives 0x0100 - 0x0200 = 0xFF00, which is also valid. c. BX + 10: This equals 0x0100 + 0x000A = 0x010A, which is valid.

All combinations are valid and yield effective addresses.