Everything in engineering requires applications of mathematics.
Is this a joke? Mathematics is the QUEEN of the sciences. she RULES engineering. Without math, you have no engineering, any kind of engineering. Think of Mathematics as the Venus of the sciences.
include <stdio.h>
int main()
{
int m, n, p, q, c, d, k, sum = 0;
int first[10][10], second[10][10], multiply[10][10];
printf("Enter the number of rows and columns of first matrix\n");
scanf("%d%d", &m, &n);
printf("Enter the elements of first matrix\n");
for ( c = 0 ; c < m ; c++ )
for ( d = 0 ; d < n ; d++ )
scanf("%d", &first[c][d]);
printf("Enter the number of rows and columns of second matrix\n");
scanf("%d%d", &p, &q);
if ( n != p )
printf("Matrices with entered orders can't be multiplied with each other.\n");
else
{
printf("Enter the elements of second matrix\n");
for ( c = 0 ; c < p ; c++ )
for ( d = 0 ; d < q ; d++ )
scanf("%d", &second[c][d]);
for ( c = 0 ; c < m ; c++ )
{
for ( d = 0 ; d < q ; d++ )
{
for ( k = 0 ; k < p ; k++ )
{
sum = sum + first[c][k]*second[k][d];
}
multiply[c][d] = sum;
sum = 0;
}
}
printf("Product of entered matrices:-\n");
for ( c = 0 ; c < m ; c++ )
{
for ( d = 0 ; d < q ; d++ )
printf("%d\t", multiply[c][d]);
printf("\n");
}
}
return 0;
}
First off, the question should be either "What math is used in Mechanical Engineering? or What is the highest level of math someone needs to take in order to become a Mechanical Engineer?"
Most college programs require through Differential Equations to earn a BS degree in ME. This means you would need to take Calculus 1, 2, and 3, Linear Algebra, and Differential Equations once you get to college. It is assumed that most students going into engineering will have no less than Pre-Calculus before entering college while most will have taken Calculus. Now each college has different requirements for fulfilling the math requirements for an engineering program. I know from my experience, Georgia Tech teaches math differently than most colleges because they combine Calc 1-3 and Linear Algebra into just 3 courses instead of 4.
My suggestion is look at the program requirements at the school you are interested in first. Second, evaluate whether you feel that you can learn the math. For those who struggle with math, if you really want to be an engineer, I suggest going to a smaller school where the class size will be smaller. This will have better student/teacher interaction so you can get more help.
wouldn't it be 16 because 16 x 3 = 48 and 16+16=32Yup that would be the answer
A Value Curve was first used by Accor, a French hotel chain in 1985. Value Curves were first described in a paper authored by W Chan Kim and Renee Mauborgne entitled, "Value Innovation: The Strategic Logic of High Growth," published in HBR in January, 1997. This paper has generated more reprints for HBR than any other paper published in HBR in the 1990's.
Value curves have been popularized in Kim and Mauborgne's "best selling" book, "Blue Ocean Strategy," HBS Press, March 2005.
A Value Curve is divided into two halves. On the left side are the Elements of Performamce. These Elements, in aggregate, define the product or service. On the right side of the curve is the value delivered to the most important customer for each of these Elements.
Value Curves with metrics are an elegantly simple way (one ppt slide) of describing project goals to project team members, stakeholders and senior management.
Dick Lee
President and Founder
Value Innovations, Inc
dick_lee@value innovations.net
+1-303-688-4143
The values of the variables will satisfy the equality (rather than the inequality) form of the constraint - provided you are not dealing with integer programming.
1+4=5
2+3=5
1x5=5
square root of 25 is 5.
All these examples equals 5 and they will never change...
Methods for finding solutions may fail for a variety of reasons:
to find the surface area of the triangle we just need to multiply the length with breath.
area=lengthXbreadth
Prime factor both numbers or expressions and use the factors the number of times it was used the MOST in either number.
6y^3=2*3*y*y*y
18y^4=2*3*3*y*y*y*y
2*3*3*y*y*y*y=18y^4
Here is the program for Gauss elimination method
#include<iostream.h>
#include<conio.h>
#include<math.h>
void main()
{float a[6][6],b[6],x[6],t,s;
int i,j,n,k;
clrscr();
cout<<"Enter the maximum no. of matrix"<<endl;
cin>>n;
cout<<"Enter th elements of matrix"<<endl;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
cin>>a[i][j];
}
}
cout<<"enter the right constant"<<endl;
for(i=0;i<n;i++)
{
cin>>b[i];
}
for(k=0;k<n-1;k++)
{
for(i=k+1;i<n;i++)
{
t=a[i][k]/a[k][k];
a[i][k]=0;
for(j=k;j<n;j++)
{
a[i][j]=a[i][j]-(t*a[k][i]);
}
b[i]=b[i]-(t*b[k]);
}
}
x[n-1]=b[n-1]/a[n-1][n-1];
for(i=n-1;i>=0;i--)
{
s=0;
for(j=i+1;j<n;j++)
{s=s+(a[i][j]*x[j]);
}
x[i]=(b[i]-s)/a[i][i];
}
cout<<"the solution is"<<endl;
for(i=0;i<n;i++)
{
cout<<"x["<<i<<"]="<<x[i]<<endl;
}
getch();
}
C program for Gauss Jordan method:
#include<iostream.h>
#include<conio.h>
#include<math.h>
void main()
{float a[6][6],b[6],x[6],t,s;
int i,j,n,k;
clrscr();
cout<<"Enter the maximum no. of matrix"<<endl;
cin>>n;
cout<<"Enter th elements of matrix"<<endl;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
cin>>a[i][j];
}
}
cout<<"enter the right constant"<<endl;
for(i=0;i<n;i++)
{
cin>>a[i][n];
}
for(k=0;k<n;k++)
{
for(i=0;i<n;i++)
if(i!=k)
{
for(j=k+1;j<n+1;j++)
{
a[i][j]=a[i][j]-(a[i][k]/a[k][k])*a[k][j]);
cout<<"the solution is"<<endl;
for(i=0;i<n;i++)
{
x[i]=(a[i][n]/a[i][i]);
cout<<"x["<<i<<"]="<<x[i]<<endl;
}
getch();
}
y = x
The product of a number and 20
Wiener-Hopf equations (′vē·nər ′höpf i′kwā·zhənz) (mathematics) Integral equations arising in the study of random walks and harmonic analysis; they arewhere g and K are known functions on the positive real numbers and ƒ is the unknown function.
I cannot be sure without knowing the context of your question. However, it might be that you are referring to the power series that defines the exponential function. It's difficult to write it down here because there is no provision for writing mathematical formulae.
Please see the link.
First we will handle the diagonalizable case.
Assume A is diagonalizable, A=VDV-1.
Thus AT=(V-1)TDVT,
and D= VT AT(V-1)T.
Finally we have that A= VVT AT(V-1)TV-1, hence A is similar to AT
with matrix VVT.
If A is not diagonalizable, then we must consider its Jordan canonical form,
A=VJV-1, where J is block diagonal with Jordan blocks along the diagonal.
Recall that a Jordan block of size m with eigenvalue at L is a mxm matrix having L along the diagonal and ones along the superdiagonal.
A Jordan block is similar to its transpose via the permutation that has ones along the antidiagonal, and zeros elsewhere.
With this in mind we proceed as in the diagonalizable case,
AT=(V-1)TJTVT.
There exists a block diagonal permutation matrix P such that
JT=PJPT, thus J=PTVT AT(V-1)TP.
Finally we have that A= VPTVT AT(V-1)TPV-1, hence A is similar to AT
with matrix VPTVT.
Q.E.D.
A fundamental unit is a unit that cannot be broken down any further. Other units are based on derivatives of these units.
http://en.wikipedia.org/wiki/Fundamental_unit
In most countries, the SI base unit system is used
http://en.wikipedia.org/wiki/SI_base_unit
Things like distance and time cannot be broken down further, so base units are used (metre and second respectively).
An example of a derived unit is km/h (kilometres per hour, often seen kmph), where kilometres are based on 1000 metres, and hours being 3600 seconds (60 x 60), where speed is equal to distance divided by time.
'uphill' it is positive
'downhill' it is negative
#include<stdio.h>
void main()
{
int a[3][3],b[3][3],c[3][3],i,j,k;
clrscr();
printf("Enter elements of A:");
for(i=0;i<=2;i++)
for(j=0;j<=2;j++)
scanf("%d",&a[i][j]);
printf("Enter elements of B:");
for(i=0;i<=2;i++)
for(j=0;j<=2;j++)
scanf("%d",&b[i][j]);
printf("A:");
for(i=0;i<=2;i++)
{
for(j=0;j<=2;j++)
printf("%d ",a[i][j]);
printf("");
//To change line.
}
printf("B:");
for(i=0;i<=2;i++)
{
for(j=0;j<=2;j++)
printf("%d ",b[i][j]);
printf("");
}
k=0;
while(k<=2)
{
for(i=0;i<=2;i++)
{
int sum=0;
for(j=0;j<=2;j++)
sum=sum+a[i][j]*b[j][k];
c[i][k]=sum;
}
k++;
}
printf("Result: ");
for(i=0;i<=2;i++)
{
for(j=0;j<=2;j++)
printf("%d ",c[i][j]);
printf("");
}
getch();
}
The standard form of the slope-intercept equation is:
y = mx + b
where "m" is the slope, and "b" is the y-intercept.
There is only one solution set. Depending on the inequalities, the set can be empty, have a finite number of solutions, or have an infinite number of solutions. In all cases, there is only one solution set.
Grams measures mass. Centimeters measures length.