Probability

There are 8 permutations of three coins. Of those, three of them have only one head, so the probability of throwing only one head is 3 in 8, or 0.375.

However, you said, "at most", and that includes the permutation that does not include any heads at all, so the probability of throwing at most one head in three coins is 4 in 8, or 0.5.

T T T *

T T H *

T H T *

T H H

H T T *

H T H

H H T

H H H

The answer depends on how many dice you roll and how often.

If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54

1/6

The probability of rolling an odd number is 3/6 (or rather, 1/2), so the probability of rolling an odd number three times in a row is 1/2^3 is 1/8 or 12.5%.

The answer depends on WHAT is landed: a number cube, a tetrahedral die, some other polyhedron, a spinner?

1/6 depends when rolling two dice? or one

No probability can be greater than 1.

An event will either not happen (p=0) or it will happen (p=1) or something in between (p>0 and p<1).

1/3

In a meta-analysis, the estimate of covariance for effect sizes is often calculated to assess the degree to which the effect sizes are correlated across studies. This covariance can be estimated using a random-effects model, which accounts for both within-study and between-study variability. Typically, it involves using the inverse of the variance of each effect size as weights in a weighted average. Understanding covariance helps in evaluating the overall heterogeneity and potential publication bias in the meta-analysis.

There is insufficient information in the question to answer it properly. Please restate the question.

6

The number is 30C3 = 30!/[3!*(30-3)!] = 30*29*28/(3*2*1) = 4060

Prob(Head in 300 tosses of a coin) = 1 - Prob(not a single H in 300 tosses)

= 1 - (1/2)300

= 1 - (4.91*10-91)

= 0.999...9998 where there are 90 9s before the 8.

With two normal six-sided dice, the maximum sum can only be 12 (6 x 2 dice), so there is zero probability of rolling a sum that adds to 16.

red is minus in math

select a marble from the jar, return it , and record times

12

1/6 chance

1260.

z-score of a value=(that value minus the mean)/(standard deviation). So a z-score of -1.5 means that a value is 1.5 standard deviations below the mean.

Anytime I see the word "Any" it's hard to give you a perfect answer. 99.9% of the time, you either need to witness the crime, have probable cause (PC) or need a warrant to make an arrest.

I'm sure there is a situation out that that might not fall into one other those but a cop still makes the arrest, I don't know.

One thing to keep in mind is that the PC comes from the officer, not the person being arrested. I have had people tell me I didn't have PC to arrest them, but the reality is I did and I'm the one that has to articulate MY PC not what joe blow thinks is PC.

No; if it is certain not to occur the probability is 0.

A z-score of 0 means the value is the mean.