0
Trigonometry
Trigonometry is a field of mathematics. It is the study of triangles. Trigonometry includes planar trigonometry, spherical trigonometry, finding unknown values in triangles, trigonometric functions, and trigonometric function graphs.
3,810 Questions
Why is the side opposite of the right triangle called a hypotenuse?
Because that is the accepted convention. The hypotenuse is the longest side of a right triangle, the side opposite the right angle. The term comes from the Greek, hypoteinousa, meaning "to stretch", and was used by Plato in the Timeus 54d and by other ancient authors. For more information, please see the Related Link below.
How calculte area of hexagon if the height have 2 units?
This must be a regular hexagon. Draw a height from the lower left vertex to the upper left vertex (2 units). Draw a horizontal diagonal thru the hexagon "left to right". These lines create 2 triangles on the left. A hexagon has angles of 60 degrees. Because the two extra lines are perpendicular so this means the triangles are 30-60-90 triangles. The altitude of these triangles is 1/2 the height of the hexagon, so these 1re 1 unit. 30-60-90 triangles have sides in the ratio of 1 to sq rt 3 to 2, since our side opposite the 60 degree angle is 1 unit, set up a proportion and the hypotenuse of the triangle is 2 (sq rt 3)/3. The other side is (sq rt 3)/3.
Now draw one triangle from the center of the hexagon to any 2 adjacent vertices. This creates an equilateral triangle. Its sides are all 2 (sq rt 3)/3. Draw an altitude, which will cut that triangle into another 30-60-90 triangle. The altitude of this triangle is 1 unit (by proportion or the Pythagorean theorem). So the area of this one triangle is 1/2 bh = 1/2 (2(sq rt 3)/3)(1) = (sq rt 3)/3.
Since there are 6 of these triangles, multiply by 6 to get the total area of the hexagon. (sq rt 3)/3 x 6 = 2(sq rt 3) answer.
How to form various types of triangle with perimeter 360m?
One possible solution which will require a really long rope and two people.Tie one end of the rope to a post. Make a loop of 360 m and tie the other end to the same post. Then one person should hold the rope and stand a short distance, x m, from the post. The other person should hold the rope so that its tight and walk in an arc on one side of the line formed by the post and the other person. This will form various triangles with base x metres and perimeter 360 m. Then the first person to take up another position a little further from the post. When the second person moves along the arc, he will form another family of triangles. In theory, the first person can make infinitesimally small movements away from the post and so this will generate infinitely many possible triangles.
Why dont you have buttons for cotangent secant cosecant?
You don't have buttons for cotangent, secant, and cosecant because you don't need them. Just invert. Cotangent is 1 over tangent, secant is 1 over sine, and cosecant is 1 over cosine.
What is the properties of equilateral triangle?
An equilateral triangle has three sides which are all of exactly the same length, and three internal angles which are all 60o.
I am not exactly sure how well these will work for you, but here are two great videos from Khan Academy and PatrickJMT that show two different ways to solve your problem. Stick with them, I know that they can be confusing.
Please see related links for helpful videos
A complex number, equations and graphs can show electromagnetic forces-for instance two wires carrying current. A formula like (z-1)/(z+1) can show the fields around two parallel wires.
8
What is does x equal when the altitude of a triangle equals x plus 9 and the hypotenuse equals 26?
For this, you need the Pythagorean theorem.
Let A equal x + 9
Let C equal 26
A^2 + B^2 = C^2
(x + 9)^2 + B^2 = 26^2
x^2 + 18x + 81 + B^2 = 676
x^2 + 18x + B^2 = 595
This doesn't help you find x, but I hope this did something!
It is an ordered pair (or triplet), which defines the distances of any point in 2 (or 3) dimensional space from a fixed point, called the origin, and along an orthogonal set of axes which cross at the origin.
Design a 3D container that would be able to hold at least 1 liter of water?
A bathtub. It will hold at least 1 litre of water.
What is a Function in Trigonometry?
There are two types of functions in trigonometry: there are functions that are mappings from angles to real numbers, and there are functions that are mappings from real numbers to angles. In some cases, the domains or ranges of the functions need to be restricted.
How do you get 1 over root 4 minus x squared to equal 1 with the substitution x equals 2 sin u?
You cannot.
1/sqrt(4 - x^2) = 1/[sqrt(4 - 4*sin^2(u)]
= 1/2 * 1/[sqrt(1 - *sin^2(u)]
= 1/2 * 1/[sqrt(cos^2(u)]
= 1/2 * 1/cos(u)
= 1/[2*cos(u)]
Whatever that is, it is not = 1.
I suspect that the question concerns integration but in for that the limits of integration are required. And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
Can an equilateral triangle be either acute or obtuse?
No. An equilateral triangle must also be equi-angular, meaning that the angles can only ever have 60 degrees.
How does one come up with the cosine of a degree?
The easiest way to do this is to use a calculator or a cosine table. If you do not have a calculator, you must try one of several other options. If you know the sine or other trigonometric value of the angle, you can use trig identities. Some angles have good cosines, like 0, 30, 45, 60, 90, and so on. These values are known, and should be memorized. Cos(0) = 1, cos(30) = SQRT(3)/2, cos(45) = SQRT(2)/2, cos(60) = 1/2, and cos(90) = 0. The list continues, but I won't go on here. You may be able to use the angle addition formulas or half or double angle formulas to find the value of your angle. If this still doesn't work, you could approximate qualitatively by looking at a cosine curve, or you could use calculus methods, like Euler's method or a Taylor or Maclauren series to approximate the value. I won't go into detail here, but you can look up any of these topics on Google or Wikipedia.
