Trigonometry

If the polygon (not ploygon!) has n vertices, the sum of the angles is (n-2)*pi radians or (n-2)*180 degrees.

Assume the first term is cos-squared(theta) rather than cos(2*theta).

6cos2(t) + 5cos(t) - 4 = 0

[6cos2(t) + 8cos(t) - 3 cos(t) - 4] = 0

[3cos(t) + 4]*[2cos(t) - 1] = 0

which gives

3cos(t) = -4 so that cos(t) = -4/3

or

2cos(t) = 1 so that cos(t) = 1/2

The first of these is clearly not a possible solution, whereas the second can hve one or more solutions, depending on the domain - which is not specified in the question.

If the initial assumption is incorrect and the first term WAS 6cos(2*theta) then using the formula for double angles:

cos(2(t) = cos2(t) - sin2(t) = cos2(t) - [1 - cos2(t)] = 2cos2(t) - 1

and so, the equation becomes

6*[2cos2(t) - 1] + 5cos(t) - 4 = 0

or 12cos2(t) + 5cos(t) - 10 = 0

Solve this quadratic equation for cos(t) and then find the values of t (or theta) within the domain specified.

(30+360*k) and (150+360*k) degrees where k is any integer.

It is the distance between opposite corners and it can be worked by using Pythagoras' theorem.

It is an obtuse angle.

iota

cos = adjacent / hypotenuse

2.9

d theta divided by 4.28 is not an equation or inequality: it is an expression. An expression cannot be solved.

5 mile = 8 km

5/8 of 65 = 40.625

Answer: 40.625 mph

The Greek letter theta

Fourth.

It means that the sides are of equal lengths and that the interior angles are of equal sizes

• 277323 dividede by 2291

When a metal can pounded into shape it is called malleable. Malleability is a physical property associated with metals where they can be hammered or pressed into a shape.

Because it is a branch of mathematics that is concerned with measurements of angles and sides of triangles, and following from that, areas and other characteristics.

It is a right angle triangle and its largest angle is 90 degrees

I just called my cardiologist's office for an answer to this one (I'm scheduled for a nuclear stress test that uses the Bruce protocol). Here's what the person who will administer my test told me:

It's the percentage of 90 degrees, 0% being no incline, 100% being straight up, perpendicular to the floor. The test begins at 1.7 mph with an incline of 10%, or 9 degrees. The incline is raised every three minutes by 2%, or 1.8 degrees. So at Level 2, the incline is 10.8 degrees, Level 3 12.6 degrees, Level 4 15.2 degrees, etc. -Joe

19

If your asking how, if you put your finger on 10 and 21, move them towards the middle until they hit the same place, if they appear next to each other then the number in between it is the median and if there is many numbers, do the first way with those numbers and there you have it, pretty simple but maybe a bit hard to understand. if you do not understand my way, ask your math teacher and she will tell you how.

Arctan (49.22) = 88.83608° or 1.55048 radians.

0.141120008

It's not. The tangent of 180 degrees is zero.

Consider tan(x) = sin(x)/cos(x). When x = 180 degrees, sin(x) = 0 and cos(x) = -1 and so tan(x) = 0