Trigonometry

It is normally a parallel line parallel to the x or y axes on the Cartesian plane.

The sine curve is exactly the same as the cosine curve shifted pi/2 radians to the left

Yes, but it is called a hyberbolic trigonometric function

2x-5=3x+6

-5-6=3x-2x

-11=x

x=-11

It is pi radians.

In a problem which can be represented by a right angled triangle, the value of the cosine of an angle can be found by dividing the length of the side adjacent to the angle with the length of the hypotenuse, so if the shorter side was 16 units long and the hypotenuse was 25 units long the cosine of the angle between those two lines would be 16/25 = 64/100 = 0.064;these cosines can easily be found on even cheap hand calculators; it is more difficult and rather obsolete to look for them in a book of mathematical tables

0.813

This question doesn't mean anything. Explain more thoroughly.

Imagine a random triangle ABC. It will make it easier if you draw it with angle C at the top. The opposite side of angle A is labelled a, the opposite side of angle B is labelled b and the opposite side of angle C is labelled c. Draw the altitude (height) from angle C so that it is perpendicular (at 90 degrees) to side c.

Looking at this triangle, find expressions for the sines of angles A and B:

sinA = h/b

sinB = h/a

Rearrange these two equations in terms of h:

h = bsinA

h = asinB

As h = h, these equations can be set equal to each other and simplified to find the sine rule:

bsinA = asinB

sinA/a = sinB/b

If you expand on this way of working, you can also find that sinA/a = sinB/b = sinC/c. You have now proven the sine rule for all triangles!

Hipparchus is the father of trigonometry.

If the polygon (not ploygon!) has n vertices, the sum of the angles is (n-2)*pi radians or (n-2)*180 degrees.

Assume the first term is cos-squared(theta) rather than cos(2*theta).

6cos2(t) + 5cos(t) - 4 = 0

[6cos2(t) + 8cos(t) - 3 cos(t) - 4] = 0

[3cos(t) + 4]*[2cos(t) - 1] = 0

which gives

3cos(t) = -4 so that cos(t) = -4/3

or

2cos(t) = 1 so that cos(t) = 1/2

The first of these is clearly not a possible solution, whereas the second can hve one or more solutions, depending on the domain - which is not specified in the question.

If the initial assumption is incorrect and the first term WAS 6cos(2*theta) then using the formula for double angles:

cos(2(t) = cos2(t) - sin2(t) = cos2(t) - [1 - cos2(t)] = 2cos2(t) - 1

and so, the equation becomes

6*[2cos2(t) - 1] + 5cos(t) - 4 = 0

or 12cos2(t) + 5cos(t) - 10 = 0

Solve this quadratic equation for cos(t) and then find the values of t (or theta) within the domain specified.

(30+360*k) and (150+360*k) degrees where k is any integer.

It is the distance between opposite corners and it can be worked by using Pythagoras' theorem.

It is an obtuse angle.

iota

cos = adjacent / hypotenuse

2.9

d theta divided by 4.28 is not an equation or inequality: it is an expression. An expression cannot be solved.

5 mile = 8 km

5/8 of 65 = 40.625

Answer: 40.625 mph

The Greek letter theta

Fourth.

It means that the sides are of equal lengths and that the interior angles are of equal sizes

• 277323 dividede by 2291

When a metal can pounded into shape it is called malleable. Malleability is a physical property associated with metals where they can be hammered or pressed into a shape.