For this you need the Atomic Mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.
125 grams Ca / (40.1 grams) = 3.12 moles Ca
1 mole = 1000 millimoles
To convert moles to millimoles, multiply known moles x 1000millimeters/1mole. For example, to convert 75 moles to millimoles:
75 moles x 1000 millimoles/1mole = 0.075 millimoles
To convert millimoles to moles, multiply known millimoles x 1mole/1000millimoles. For example, to convert 5300 millimoles to moles:
5300 millimoles = 1 mole/1000 millimoles = 5.3 moles
There are 1000 millimoles in a mole. You need to divide by 1000. 1250/1000 gives you 1.25 moles.
1 millimole=o.oo1 so, 2800*0.001=2.8
1.250 mol
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.
This question is solved with the help of mole concept . 1 mole of anhydrous calcium carbonate weighs 40+12+48=100 gm . 1.25 mole of similar anhydrous calcium carbonate will be 100* 1.25 = 125 gm
The Molarity of the solution is .901
There are at least three kinds of sodium sulfide, but assuming that the question refers to the most common one with the formula Na2S, its gram formula mass, the mass corresponding to molar mass for covalently bonded compounds, is 78.04. Therefore 125.00 constitutes 125.00/78.04 or 1.6017 "moles".
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
No such thing as HSO in chemistry. If you're referring to H2SO4, which is sulfuric acid, then 125 grams of it would be: H2SO4 = 98g/mol; 98/1=125/x; solve for x to get about 1.28 moles.
There is 125 milliliters in 125 grams. This is when converting liquid ingredients. To convert grams to milliliters the density of the ingredients needs to be known.
There is 125 grams in a cup. So 450 is 3.6 cups
Each cup is approximately 125 gm
125 g nickel is equivalent to 2,13 moles.
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
To convert grams into deciliters, you would divide by 100. This means that 1 gram of flour equals 0.01 deciliter.
148 grams minus 125 grams is 23 grams.
125 grams is 4.41 ounces.
Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.
125 grams = about 0.276 pounds.