Use stoichometry to figure this out.
1 mole Fe * 56 g Fe
...............1 mole Fe
7.4 moles iron (55.85 grams/1 mole Fe) = 413.29 grams iron
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
241.86 grams per mole
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
Balanced equation. Fe(OH)3 + 3HNO3 --> Fe(NO3)3 + 3H2O 63.8 grams Fe(NO3)3 (1 mole Fe(NO3)3/241.88 grams)(1 mole Fe(OH)3/1 mole Fe(NO3)3 = 0.264 moles iron III hydroxide needed ==========================
7.4 moles iron (55.85 grams/1 mole Fe) = 413.29 grams iron
100 grams oxygen (1 mole O/16 grams)(2 mole Fe/3 mole O) = 4.17 moles iron --------------------------
For this you need the atomic mass of Fe. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel..410 grams Fe / (55.9 grams) = .00733 moles Fe
2Fe + 3S >> Fe2S3 48.0 grams S (1 mole S/32.07 g)(2 Fe/3 mole S)(55.85 g/1 mole Fe) = 55 .7 grams of iron needed
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
241.86 grams per mole
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
Balanced equation. Fe(OH)3 + 3HNO3 --> Fe(NO3)3 + 3H2O 63.8 grams Fe(NO3)3 (1 mole Fe(NO3)3/241.88 grams)(1 mole Fe(OH)3/1 mole Fe(NO3)3 = 0.264 moles iron III hydroxide needed ==========================
Find iron (Fe) on the periodic table the biggest number (at the bottom) is the mass number 1 mole is that number in grams. you can work it out from there.
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3
Use the equation; mass=moles*gramformulamass or m=n*gfm m=2*55.8 = 111.6g in two moles of Iron gfm or the molecular mass of a compound can be found by adding the Relative atomic masses of each element in the compound together. For example - Carbon dioxide CO2 The formula contains 1 Carbon atom and 2 Oxygen atoms (RAMs should be found in a datasheet/book or provided in the question. RAM = relative atomic mass) RAM Carbon = 12 RAM Oxygen = 16 gfm of CO2 = 12 + 32 = 44 or 1mole of CO2 = 44g
1 mole Fe = 55.845g Fe 1 mole Fe = 6.022 x 1023 atoms Fe 23.0g Fe x (1 mole Fe/55.845g Fe) x (6.022 x 1023 atoms Fe/1 mole Fe) = 2.40 x 1023 atoms Fe