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7,8 g of NaCl contain 0,814.10e23 formula units.
The answer is 5,21131981201352.10e23 formula units of silver nitrate.
1 mole NaCl = 6.022 x 1023 formula units NaCl 2.9 x 1021 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl = 0.0048 mole NaCl
22,4 g SnO2 is 0,15 from a formula unit.
0.0482 moles Na2SO4 x 6.02x10^23 form.units/mole = 2.91x10^22 formula units
mom
8
7,8 g of NaCl contain 0,814.10e23 formula units.
1 mole CaCl2 = 6.022 x 1023 formula units CaCl2 1.26 x 1024 formula units CaCl2 x 1mol CaCl2/6.022 x 1023 formula units CaCl2 = 2.09 moles CaCl2
The answer is 4,328.1023formula units (not molecules).
A mole of substance contains Avogadros number (6.022 X 1023) formula units or molecules). 5.33 mol will contain 5.33 X 6.022 X1023 = 3.209 X1024
10 formula units
The term molecule is not adequate for an ionic compound; correct is formula unit.60 g NaCl contain the equivalent of 1,026 formula units.
The answer is 5,21131981201352.10e23 formula units of silver nitrate.
How many grams of NaCl are present in 8.39x10^22 formula units of NaCl?
The number of formula units is 0,602 214 085 7.10e23.
How many formula units of Fe2O3 are used in the process to produce 740 g of Fe?