CH is not a molecule.
1/80 = 0.0125
The equation to find molar concentration is C= n/v (concentration= moles/volume). For 80g of glucose, you would first need to find the number of moles; n= m x mm (moles= mass x molar mass). Then you can input that number into the equation C= n/v.
Water is; H2O so; 80 * 2 = 160 hydrogen atoms
2 mol/kg
80 protons
Please check the workings if you wish to understand how the problem is solved. At S.T.P., 1 mole of any gas = 22.4 Litres(It's a given. I assume you know this one.) Therefore, 1 Litre of a gas = 1/22.4 = 0.0446 moles Out of these 0.0446 moles, 80% is Oxygen gas. Number of moles of Oxygen gas = 0.0446 x 80% = 0.0446 x 80/100 = 0.0357 moles. 1 mole of any gas = 6.02 x 1023 units (This is also a given, known as the Avagadro's constant.) Therefore, 0.0357 moles = 0.0357 x 6.02 x 1023 = 2.15 x 1022 molecules of Oxygen gas.
The atomic mass of the N atom is 14.0. This means that 1 mole of N atoms weighs 14.0g.Mass of 5.0 moles of N atoms (or 2.5 moles of diatomic nitrogen molecules, N2)= 5.0 x 14.0= 70g
The relationship between number of moles and mass is: n = m/MW Where n is the number of moles, m is the mass in grams and MW is the molecular weight (or molecular mass). Subsituting the numbers into the equation: 2.5 mol = m/32 (from O2(g), 16 from each oxygen) m = 2.5 * 32 = 80 grams This also means that there is approximately 1.5 x 1024 molecules of O2 in your sample.
The molar mass of an element is its atomic weight in grams. The atomic weight is on the periodic table. 1 mole C = 12.0107 g C. To calculate the number of moles in 80 g of C, do the following: 80 g C x (1 mole C/12.0107 g C) = 6.66 mole C = 7 mole C* *This answer has been rounded to the proper number of significant figures. When multiplying or dividing, the answer is rounded to the fewest significant figures used in the calculation. 80 only has one significant figure. Refer to the related link below concerning significant figures.
The average is the sum of the elements divided by the number of elements In other words, 80%+82.54% then divide the sum by 2.
To calculate 30 percent of a number, multiply the number by 0.3. For example, 30 percent of 80 is equal to 80 x 0.3 = 24.
2 moles 80/40= 2
Divide the amount of months by the number of months in a year (12). Thus the number of years in 80 months is 80/12= 6.666666666. Therefore the number of years in 80 months is roughly 6 and a half.
The mass number of potassium is about 39. The mass number of bromine is about 80. Total is 119. 119* 2.5 = 297.5. So 297.5 grams of potassium bromide has got 2.5 gram moles.
You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
The answer is B, 8.0 x 10^1 There are 6.023 x 10^23 atoms in one mole, of any substance. So simply divide 4.8 x 10^25 by 6.023 x 10^23, to get about 79.69 which if you convert into scientific notation, is about 8.0 x 10^1 the answer for me was A but that's on novanet
molar mass SO3 = 80 g/mole. 1.12 moles x 80 g/mole = 89.6 grams