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Calculate the pH of a solution prepared by diluting 3.0 mL of 2.5 M HCl to a final volume of 100 mL with H2O?
Wiki User
∙ 10y ago
Because HCl is a strong acid, it dissociates completely to H + Cl. Therefore,
3.0 mL x 2.5 M HCl = 7.5 meq of H+ . In 100 mL of solution, this is 0.075 M H+.
pH= - log [H] = - log (0.075) = - (-1.1) = 1.1 (two significant figures)
Wiki User
∙ 10y ago
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