Need moles NaCl first.
17.52 grams NaCl (1 mole NaCl/58.44 grams)
= 0.29979 moles NaCl
=====================Now.
Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters )
Molarity = 0.29979 mole NaCl/2 Liters
= 0.1499 M NaCl
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Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
If 1,1 is grams the molarity is 0,317.
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
Molarity = moles of solute/volume of solution. 0.73 grams MgCl2 (1mol/95.21g ) = 0.00767 moles/0.300 Liters ( to get M, not mM ) = 2.6 X 10^-2 M
The molarity is 0,125 M.
Molarity (M) = mole of solute (mol)/volume of solution that it is dissolved into (L) Make sure that the volume is converted to L if it isn't already, otherwise you will get wrong answers.
This sodium hydroxide solution has a molarity of 0,25.
- measuring the mass of this compound and the volume (or mass) of the solution - by chemical analysis (and determination of the concentration of this compound) If you know the molarity, multiply moles by molecular weight and adjust per the volume you have. If you don't know the molarity, a simple means is to just evaporate the solvent and weigh the remaining compound
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
Molarity = Grams/(Molecular Weight X Volume)
Molarity = Grams/(Molecular Weight X Volume)
It depends highly on the compound to be dissolved and the solvent. Molarity is measured my moles per litre, and if you don't know the molar mass of the compound, you can't work out the molarity.
If 1,1 is grams the molarity is 0,317.
The molarity is 2,973.