Math and Arithmetic

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Need moles NaCl first.

17.52 grams NaCl (1 mole NaCl/58.44 grams)

= 0.29979 moles NaCl

=====================Now.

Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters )

Molarity = 0.29979 mole NaCl/2 Liters

= 0.1499 M NaCl

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0Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.

Molarity = moles of solute/volume of solution 2.24 grams NaOH (1mol/33.998g) = 0.0659 moles NaOH/0.5 liters = 0.132 Molarity of NaOH

4.00 grams of NaOH have been added to 2.00 liters of water. The molarity of this solution is?

- measuring the mass of this compound and the volume (or mass) of the solution - by chemical analysis (and determination of the concentration of this compound) If you know the molarity, multiply moles by molecular weight and adjust per the volume you have. If you don't know the molarity, a simple means is to just evaporate the solvent and weigh the remaining compound

Molarity = Grams/(Molecular Weight X Volume)

Molarity = Grams/(Molecular Weight X Volume)

Molarity = Grams/(Molecular Weight X Volume)

Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl

Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.

Molarity = moles of solute/volume of solution so, 29.4 grams sounds about right.

Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity

Molarity is moles/liter. From moles/liter, you can calculate mass in grams by converting the moles to grams using molar mass, and then use the volume to calculate the final mass in that volume. Thus,moles/liter x gram/mole x liters = mass in grams

If 1,1 is grams the molarity is 0,317.

Molarity = moles of solute/volume of solution so, 125 grams of NaCl (1mol NaCl/58.44 grams NaCl) = 2.1389 moles NaCl/400 Liters = 0.00535 M NaCl

31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity

M = n ÷ V M-Molarity (mol/l) n- moles V- volume in liters. Volume cannot be expressed in grams....

Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )

Increasing the amount of the solute in the solution the molarity and the density of this solution increases.

Calculating molarity of this solution requires the variables of solute mass (in kilograms), molecular weight of the solute (in kilograms per mole), and solution volume to be known (in liters). In this example we only have the variables of a mass of .056 kilograms and volume of .959 liters.

Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------

molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L

All you have to do is convert the 6.5 g HCl solution into moles, and then plug that value into the molarity formula. If you need help, here are the formulas: # mol = (mass of substance)/(molar mass) - the molar mass is just the molecular mass of the substance expressed in grams :) Molarity (M) = (# mol solute)/(# L solution) - the solute, in this case, is the HCl, and the solution is just one, based on your question Happy Calculating!!!

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