Supposing you want to get a total volume of 1.00 Litre of 0.01 M HCl (= 0.01 mol/L), you've to take 1/100th of this, being 10.0 mL of the 1M HCLsolution
and add this to about 0.9 L distilled water, mix it and then fill up to exactly 1.00 Litre.
Dilution equation:
V1 * c1 = V2 * c2
Filled in (use same units on each side!):
1.00 (L) * 0.01 (M) = V2 (L) * 1 (M) ==> V2 = 0.01 L = 10.0 mL
10.82
About 13M. You can assume it is 13M if you don't need an exact concentration (like if you need a ~1M HCl solution for an extraction or whatever) but if you need an exact concentration (for a titration, for example) then you will need to standardize your HCl first.
Yes! A HCl molar concentration of 1 is dangerous. If you are referring to moles, then it depends on how much it has been diluted.
The Mole is a unit for amount of substance. Molarity, on the other hand, is a unit for concentration of a solution. 1M = 1 mol/dm^3.
what is the role of HCL in the DNase experiment
10.82
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
About 13M. You can assume it is 13M if you don't need an exact concentration (like if you need a ~1M HCl solution for an extraction or whatever) but if you need an exact concentration (for a titration, for example) then you will need to standardize your HCl first.
Yes! A HCl molar concentration of 1 is dangerous. If you are referring to moles, then it depends on how much it has been diluted.
Preparing 1N HCl for 1L. 1N=1M in HCl. Conc. HCl= 12M M1V1=M2V2 12*V1=1*1000 V1=1000/12 V1=83.33ml 1N HCl= 83.33ml of Conc. HCl in 1L of water 2N HCl= 167ml of Conc. HCl in 1L of water.
.5M
The Mole is a unit for amount of substance. Molarity, on the other hand, is a unit for concentration of a solution. 1M = 1 mol/dm^3.
what is the role of HCL in the DNase experiment
1N HCl is also 1M HCl because it is mono-protic. Therefore 36.5 g of HCl is required per liter or 3.65%. Simply take 100 g of 37% HCl and make up to the 1 liter mark on the volumetric flask. Check the value by titration against 1M NaOH. It should be perfect. If very slightly strong dilute very slightly (calculate) with water and re-standardize.
By 10-fold dilution
Exactly how you prepare will depend on what you are starting with. Typically to make a 1 M HCl solution, you will be starting with a stock solution of more concentrated HCl that you will then dilute. See the Related Questions for complete instructions on how to prepare a solution by diluting a stock solution. 1M HCl Solution*Concentrated HCl. its 37.5%. *The density of concentrated HCl is 1.189g/ml we will need this number as well, and of course the atomic mass of HCl 36.46 * Calculation=((37.5/100)(1000)(1.189))/36.46 = 12.2M *If HCl concentrated is 12.2 M then to make a 1L solution of 1M HCL (12.2) x = 1(1) x = 1(1)/(12.2) x=0.082ml/ml of water x = 82mL HCl per liter
because hcl is more acidic than ch3cooh. ch3cooh (ethanoic acid) is a weak acid whereas hcl is a very strong acid.