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How to prepare 250ml of a 2m solution of potassium chloride?
111.72
How do you prepare a 2 molar salicylic acid solution?
take 276 gm of salicylic acid in 1000 ml water to prepare 2M solution of the salicylic acid.
How do you make 2M HCL in 100ml from 36 percent Hcl?
1M contains 43.1ml in 500ml, 2M contains 86.2ml in 500ml
How many grams of hydrochloric acid are needed to make a solution of 2 molar?
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
What is the pH of 2M hcl?
- log (2) = - 0.3
How to prepare 250ml of a 2m solution of potassium chloride?
111.72
How much hydrochloric acid would a 2M solution contain?
2 moles of HCl for every liter of solution.
How do you prepare a 2 molar salicylic acid solution?
take 276 gm of salicylic acid in 1000 ml water to prepare 2M solution of the salicylic acid.
How many moles of NaI would you need to prepare 2L of a 2M NaI solution?
599.6
How do you prepare 0.02 M of HCl?
Preparing 1N HCl for 1L. 1N=1M in HCl. Conc. HCl= 12M M1V1=M2V2 12*V1=1*1000 V1=1000/12 V1=83.33ml 1N HCl= 83.33ml of Conc. HCl in 1L of water 2N HCl= 167ml of Conc. HCl in 1L of water.
How would you prepare 30mL of a 5M NaCl solution from a 2M NaCl stock solution?
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
How do you make 2M HCL in 100ml from 36 percent Hcl?
1M contains 43.1ml in 500ml, 2M contains 86.2ml in 500ml
How many grams of hydrochloric acid are needed to make a solution of 2 molar?
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
What is the pH of 2M hcl?
- log (2) = - 0.3
How do you prepare 2M 100 ml sodium hydroxide solution?
Just dissolve 8g solid NaOH in 100 mls. distilled water.
How do you prepare 2M HCl solution from HCl?
Step 1 The easiest way to make a 5 Molar HCl solution is following Consider that your stock HCl concentration is 37.5% and S.G 1.189 gms / ml and formula weight for HCl is 36.46 gms / mole Step 2 Now determine the Molarity of the stock Solution Percentage x S.G / Molecular Weight 37.5 x 1.189 x 1000 / 100 * 36.46 Molarity of Concentrated - Stock HCl = 12.23 moles / liter or M Now, to make a 5 molar solution MiVi = MfVf Vi = Mf x Vf / Mi Vi = 5 x 1 / 12.23 Vi = 0.409 liter or 408.9 ml Imran Malik Dubai
What is the concentrate of 2M NaCl?
2M NaCl is a equivalent to a solution with 116,88 g NaCl in 1 L water.
