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How many moles of Ag contain 4.4910e23 atoms Ag?
1 mole Ag = 6.022 x 1023 atoms Ag 4.4910 x 1023 atoms Ag x 1 mole Ag/6.022 x 1023 atoms Ag = 0.7468 mole Ag
How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
How many atoms in AgI?
Only two atoms: Ag and I.
How many atoms of gold are in 5 grams of gold?
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
How many moles of silver (Ag) are present in a sample of 3.8 10 to the power of twenty four atoms Ag?
The answer is 6,31 moles Ag.
How many atoms are in 1 mole of Ag?
6.023*1023
How many moles of Ag in 8.9 x 1024 atoms Ag?
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
How many grams are therein 2.31024 atoms of silver?
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
How many mols are there in 5.42x10 to the 24 of atoms Ag?
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
How many ag atoms are there in 0.0001 grams of Ag.Molar mass of Ag is 108 gram per mole?
Using your molar mass. 0.0001 grams silver (1 mole Ag/108 grams)(6.022 X 1023/1 mole Ag) = 5.58 X 1017 atoms of silver =====================
How many atoms of Ag are in 1.6grams?
1 mole Ag = 6 x 10^23 atoms = 107.87g. ? atoms = 1.6g by simple proportion it follows that: 1.6 x 6 x 10^23 / 107.87 = ...
How many atoms of silver in 10.8g?
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
