The number of atoms of lead is 6,68.10e23.
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149 g of calcium contain 22,39.10e23 atoms.
2.50 g MgBr2 x 1 mole MgBr2/184 g x 2 mole Br/mole MgBr2 = 0.0272 moles Br^-0.0272 moles Br^- x 6.02x10^23 anions/mole = 1.6x10^22 anions
27,30.10e23 atoms
Taking Avogadro constant to be 6.022 X 1023The no. corresponds to 1 mol Br atoms = 80 g(Approx)
The standard atomic weight of platinum is 195,084 g.195,084 g-------------------------------1 mol250 g-------------------------------------x molx = 250/195,084 = 1,28 mol platinum
7,61 g LiBr contain 6,99 g Br.6,99 g Br is 0,087 moles.
445 g
The number of atoms of lead is 6,68.10e23.
250 g = about 0.55116 pounds.
250 g = 0.25 kgTo convert from g to kg, divide by 1000.
how many planets are there? how many planets are there? how many planets are there?
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
149 g of calcium contain 22,39.10e23 atoms.
250 mg = 0.25 g
2.50 g MgBr2 x 1 mole MgBr2/184 g x 2 mole Br/mole MgBr2 = 0.0272 moles Br^-0.0272 moles Br^- x 6.02x10^23 anions/mole = 1.6x10^22 anions