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1.28 x 10^21 atoms
Wiki User
∙ 12y ago
To find the number of atoms in 0.0728 g of PCl3, you first convert the mass to moles using the molar mass of PCl3 (137.33 g/mol). Then, you use Avogadro's number (6.022 x 10^23) to convert moles to atoms. The number of atoms in 0.0728 g of PCl3 would be approximately 2.69 x 10^21 atoms.
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27,30.10e23 atoms
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6,687.1023 chlorine atoms
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27,30.10e23 atoms
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78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
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156,86.1020 atoms of uranium in 6,2 g uranium
how many atoms are in 22 g of argon?
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