I assume you mean atoms.
2.4 X 10^24 atoms SO3 ( 1mol SO3/6.022 X 10^23 ) = 3.985 mol
Wiki User
∙ 14y agoWiki User
∙ 11y ago2x(6.02 x 1023)x4 = 4.816 x 1024 atoms
Wiki User
∙ 8y agoThe answer is 3,38 moles.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
48
The formula of the compound shows that each molecule contains 4 total atoms, 3 of oxygen and one of sulfur. Therefore, the number of atoms in 1.14 moles is 4 X 1.14 X Avogadro's Number or about 2.75 X 1024 atoms.
In each sulfur trioxide molecule there is one sulfur atom and three oxygen atoms, giving a total of four atoms. In 1.14 moles of sulfur trioxide, there would be 1.14 x 6.02 x 10^23 = 6.87 x 10^23 molecules. Accordingly, there would be 4 x 6.87 x 10^23 = 2.75 x 10^24 atoms in total.
SO3, Sulfer Trioxide. Or SO3(2-), Sulfite.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.
To find the number of moles, you first need to calculate the molar mass of SO3, which is 80.06 g/mol. Then, you can use the formula: moles = mass / molar mass. Thus, for 20g of SO3, you would have 20g / 80.06 g/mol = 0.25 moles of SO3.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
48
For the reaction SO2 + O2 -> SO3, the stoichiometry is 1:1. So, if 4 moles of SO2 are oxidized, then 4 moles of O2 are required for the complete reaction.
To find the mass of 1.12 moles of SO3, you need to multiply the number of moles by the molar mass of SO3. The molar mass of SO3 is approximately 80.06 g/mol. Therefore, the mass of 1.12 moles of SO3 would be 89.67 grams (1.12 moles * 80.06 g/mol).
The formula of the compound shows that each molecule contains 4 total atoms, 3 of oxygen and one of sulfur. Therefore, the number of atoms in 1.14 moles is 4 X 1.14 X Avogadro's Number or about 2.75 X 1024 atoms.
How many cups are in 5555555555 gallons
In each sulfur trioxide molecule there is one sulfur atom and three oxygen atoms, giving a total of four atoms. In 1.14 moles of sulfur trioxide, there would be 1.14 x 6.02 x 10^23 = 6.87 x 10^23 molecules. Accordingly, there would be 4 x 6.87 x 10^23 = 2.75 x 10^24 atoms in total.
Al2(SO3)3.
First, calculate the molar mass of O2 (32 g/mol) and find the number of moles in 8.0 g (0.25 mol). Since S is in excess, all O2 will be consumed. From the balanced equation, 2 mol O2 produces 2 mol SO3, so 0.25 mol O2 will produce 0.25 mol SO3.