1 mole Ag = 6 x 10^23 atoms = 107.87g.
? atoms = 1.6g
by simple proportion it follows that:
1.6 x 6 x 10^23 / 107.87 = ...
4.82 × 1021
6.023*1023
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
76.2 mol Ag
In one Ag2O there are 2 'Ag' (silver) atoms and 1 'O' (oxygen) atom: three in total
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
One formula unit of AgI contains one atom of silver (Ag) and one atom of iodine (I), so there are a total of two atoms in AgI.
That is 3 teaspoons.
The answer is 6,31 moles Ag.
6.023*1023
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
16 grams = 16,000 mg