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1 mole of HCl is 36.5g so 0.25 moles are 36.5 x 0.25 = 9.125g
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How many moles of HCL are there in 108 grams of the substance?
The answer is: 2,96 moles.
How many moles HCl in 8.3 g HCl?
There are 0.224 moles of HCl in 8.3 g of HCl. This is calculated by dividing the mass of HCl by its molar mass (36.46 g/mol).
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
How many moles of HCl are on 10 grams of substance?
To find the number of moles, you need to divide the given mass (10 grams) by the molar mass of HCl (36.46 g/mol). This will give you approximately 0.274 moles of HCl.
How many moles of solute are in 50 mL of a 12 M HCl solution?
To find the number of moles of solute in the solution, first, calculate the amount of HCl in grams using the formula: moles = molarity x volume (in liters). Then, convert the grams of HCl to moles by dividing by the molar mass of HCl (36.46 g/mol).
How many moles HCl in 8.3 g HCl?
There are 0.224 moles of HCl in 8.3 g of HCl. This is calculated by dividing the mass of HCl by its molar mass (36.46 g/mol).
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
How many moles of HCL are there in 108 grams of the substance?
The answer is: 2,96 moles.
How many moles of HCl are on 10 grams of substance?
To find the number of moles, you need to divide the given mass (10 grams) by the molar mass of HCl (36.46 g/mol). This will give you approximately 0.274 moles of HCl.
How many grams of HCl are needed to obtain 1.0 liter of a 0.22 M HCl solution?
To calculate the number of grams of HCl needed, you can use the formula: mass (g) = volume (L) x concentration (mol/L) x molar mass (g/mol) Here, the volume is 1.0 L, the concentration is 0.22 M, and the molar mass of HCl is approximately 36.5 g/mol. Plugging these values into the formula, you will find that you need approximately 8.03 grams of HCl.
How many moles of HCL are in 2.5 L of 0.5 M solution ?
There are 1.25 moles of HCl in 2.5 L of a 0.5 M solution of HCl. This can be calculated by multiplying the volume (2.5 L) by the concentration (0.5 mol/L).
How many grams are 0.7 moles of HCL?
The answer is 25,522 g.
How would you prepare 17.2 L of a 3.8 M HCl solution?
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
How many moles of atoms are present in 154 g of HCl?
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
How many grams of zinc can react with 225ml of 0.200 m HCl solution?
To calculate the grams of zinc needed to react with the HCl solution, you first need to determine the number of moles of HCl present in 225 ml of 0.200 M solution. Then, you can use the balanced chemical equation for the reaction between zinc and hydrochloric acid to determine the mole ratio between zinc and HCl. Finally, you can convert the moles of HCl to grams of zinc using the molar mass of zinc.
How many moles are in 291.68 grams of hydrochloric acid?
To calculate moles of HCl in 291.68 grams, use the molar mass of HCl which is 1 + 35.5 = 36.5g/mole. 291.68 g x 1 mol/36.5 g = 7.99 moles HCl (3 sig figs)
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
