60g (apex)
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
100 grams oxygen (1 mole O/16 grams)(2 mole Fe/3 mole O) = 4.17 moles iron --------------------------
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
For this you need the atomic (molecular) mass of Fe2(SO4)3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Fe2(SO4)3=400.1 grams768 grams Fe2(SO4)3 / (400.1 grams) = 1.92 moles Fe2(SO4)3
Let's see. 3 moles gold (197.0 grams/1 mole Au) = 591 grams of gold ----------------------------- 10 mole iron (55.85 grams/1 mole Fe) = 558.5 grams of iron ----------------------------- So, 3 moles of gold has more mass that 10 moles of iron. (heavier)
60
60 g
150 grams NH3 (1 mole NH3/17.034 grams)(3 mole H/1 mole NH3)(1.008 grams/1 mole H)= 26.6 grams hydrogen=================17 g of ammonia has 3 g of hydrogen.So 150 g of ammonia will have 26.5 g of hydrogen
3 moles of ammonia is 51grams. One mole is 17 grams.
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
100 grams oxygen (1 mole O/16 grams)(2 mole Fe/3 mole O) = 4.17 moles iron --------------------------
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
7.56 X 1011 atoms of oxygen (1 mole O/6.022 X 1023)(1 mole V2O3/3 mole O)(149.88 grams/1 mole V2O3) = 6.27 X 10 -11 grams vanadium oxide ===========================
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5
90.19 grams/mole