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The nitrogen iodide is NI3.
106.7 grams
1.60 x 10^24 molecules
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
1.88*10^24
The nitrogen iodide is NI3.
106.7 grams
107.5 g N2I6
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
Quite a few! 8.2 X 10^22 atoms of N2I6 (1 mole N2I6/6.022 X 10^23)(789.42 grams/1 mole N2I6) = 107 grams of N2I6 (Would have been peanuts without all that iodine! )
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
1 mole NCl3 = 120.366g NCl3 = 6.022 x 1023 molecules NCl3 8.2 x 1022 molecules NCl3 x 120.366g NCl3/6.022 x 1023 molecules NCl3 = 16g NCl3 rounded to 2 significant figures
1.64×1022 molecules
2.05×1022 molecules
To find the mass, we divide by Avogadro's number to find the amount of moles. We then multiply the moles by the molar mass of the compound which is 60.08 grams. Doing all of this, we get a mass in grams of 5.59 grams.
As every nitric oxide molecule has three atoms, this amount of molecules have 3.9 x 1022 atoms.
To find the mass, we divide by Avogadro's number to find the amount of moles. We then multiply the moles by the molar mass of the compound which is 60.08 grams. Doing all of this, we get a mass in grams of 5.59 grams.