The molecular weight of NaCl is 58.44. So you would need to add 116.88 g of NaCl into 1 L of water.
Molarity X Required volume X Molecular weight
2 M/L X 1 L X 58.44
=116.88 g/L
If the volume is 1 L the answer is 116,88 g NaCl.
We need 116, 88 g sodium chloride.
290 grams
The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.
The molecular weight of the carbonate ion is 60 grams per mole.
The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.
The only difference is the name of the unit; the numerical values are the same. However, the value in amu is the mass of a single molecule, while the molecular weight in grams is the mass of Avogadro's number of molecules. The mass of Avogadro's number of molecules is called a Gram-mole. The molecular weight of , say, Hydrogen H2 is 2 amu. A gram mole of this would be 2 grams. The molecular weight in grams is the weight of this molecule in real grams and is an extremely small value.
2
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
the molecular weight of a substance expressed in grams
2.02 grams/mole
Put 100 grams in a beaker and and around 500 mls of water until it dissolves, then top up the beaker to a liter. That is your 10% solution. The percentage solution is a ratio of the weight of the compound to the weight of the final solution.
62.72
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl