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The molecular weight of NaCl is 58.44. So you would need to add 116.88 g of NaCl into 1 L of water.

Molarity X Required volume X Molecular weight

2 M/L X 1 L X 58.44

=116.88 g/L

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9y ago
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9y ago

If the volume is 1 L the answer is 116,88 g NaCl.

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9y ago

We need 116, 88 g sodium chloride.

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Q: How many grams are needed to make 1L of a 2 molar solution of NaCl with a molecular weight of 58?
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