How many grams are therein 2.31024 atoms of silver?

Answer 1

• First from atoms to mole (Avogadro's number)

2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Ag

• and from mole to gram (via molar mass)

3.82 mole * 107.9 g/mole = 412 g Ag

Answer 2

(2.3 x 1024 atoms Ag) x (1 mole Ag/ 6.022 x 1023 atoms Ag) x (107.0 g Ag/ 1 mole Ag) = 412.1056 g Ag

Convert the atoms Ag to moles of silver. Then convert the moles to grams.

Answer 3

There are 6.022*10+23 particles (eg. atoms) in one mole, thus:

2.3*10+24 / 6.022*10+23 = 38.19 = 38 moles Ag-atoms

Answer 4

2.3 x 1024 atoms Ag * (1 mol Ag/ 6.022 x 1023 atoms Ag)*(107.9 g Ag/mol Ag) =

412.1 g of Ag

Answer 5

2.31024 atoms? this doesnt make sense...

if you mean 2,31024 moles, then m= Ar(Ag) x 2,31024= 249,01 g

Answer 6

2.3 X 1024 atoms of silver (1 mole Ag/6.022 X 1023)(107.9 grams/1 mole Ag)

= 412 grams silver

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Answer 7

1 mole Ag = 107.8682g = 6.022 x 1023 atoms

1.80 x 1023 atoms Ag x (107.8682g)/(6.022 x 1023 atoms) = 32.2g Ag

Answer 8

grams = 7.4 x 1024 x (Atomic Mass of silver) / (6.023 x 1023)atomic mass of silver = 107.868

Answer = 1325.2917 grams

Answer 9

6,022140857.1023 atoms--------------------------107,8682 g
7,4.1024 atoms-----------------------------------------x

x = 1325,48 g