First.
Molarity = moles of solute/Liters of solution
0.22 M HCl = X moles/1.0 L
= 0.22 moles HCl
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Second.
0.22 moles HCl (36.458 grams/1 mole HCl)
= 8.0 grams hydrochloric acid needed
===========================
148g
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
try adding ten grams to every liter
30 grams
The molarity is 2,973.
148g
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
290 grams
try adding ten grams to every liter
One liter of Benedict's solution contains 173 grams sodium citrate, 100 grams sodium carbonate, and 17.3 grams cupric sulfate pentahydrate.
Molarity = moles of solute/volume of solution. 1 liter = 1000 millilitetrs 3.00M = X Moles/1000ml = 3000 millimoles, or 3 moles NaCl 3 moles NaCl (58.44g NaCl/1mol NaCl ) = 175.32 grams needed. About 4/10 of a pound of salt.
Put 100 grams in a beaker and and around 500 mls of water until it dissolves, then top up the beaker to a liter. That is your 10% solution. The percentage solution is a ratio of the weight of the compound to the weight of the final solution.
35
30 grams
The molarity is 2,973.
The answer is 0.8 L: Let's think of a '6/15 solution' as meaning 6/15 grams per litre, and the solution we're trying to obtain is 10 grams/litre. In our final solution, we'll have 6 grams resulting from the one litre of weaker solution, and 15v grams from the stronger (where v is the volume of stronger added). Deviding this total mass by the total volume of the solution, we arrive at the wanted concentration of 10 grams/litre. Algebraicly: (15v + 6)/(1+v) litres = 10 15v + 6 = 10 + 10v 5v = 4 v = 4/5 = 0.8 L Hope this helps.
0.9051 moles Mg per liter of solution. Molarity is the amount of moles per liter of solution. So just divide the number of grams of Mg by its molar mass then divide that by the number of liters