The molcular weight of PCl3 is
30.97 + (35.45 X 3) = 137.32
The amount of P required to make 5.49 g
(30.97 / 137.42) X 5.49 = 1.23g
319g Cl2 are needed.
Call the unknown mass x. The Law of Constant Proportions states that x/13 must equal 31/71, or x must be (13)(31)/71 or about 5.7 grams, to the justified number of significant digits.
201
326g
The needed mass of sodium is 91,659 g (for 2 moles H2).
3,42 moles of phosphorus trichloride have 469,6686 g.
The daily requirement of phosphorus is 800. How many grams of phosphorus are needed?
10.1 grams
16,45 g nitrogen are needed.
319g Cl2 are needed.
A lot
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
Call the unknown mass x. The Law of Constant Proportions states that x/13 must equal 31/71, or x must be (13)(31)/71 or about 5.7 grams, to the justified number of significant digits.
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
mass of CaCO3 = 246 grams
201
0.125 mole