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How many mole h2o have in this reaction caco3 plus 2hcl---cacl2 co2 h2o?
Wiki User
∙ 13y ago
Molar ratio's in this balanced equation: 1 + 2 --> 1 + 1 + 1 (H2O) respectively
Wiki User
∙ 13y ago
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What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many grams of calcium in 34.5 of Ca CO 3?
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
Calculate the number of mole of CO2 generated by the reaction of caco3 equals cao plus CO2 when 500 g cao is produce?
The decomposition reaction of calcium carbonate produces calcium oxide and carbon dioxide in a one to one ratio. 500 grams of CaO is 8.92 moles, so 8.92 moles of carbon dioxide are produced.
Write a Balanced equation between HCl and CaCO3?
2 HCl + CaCO3 -> CaCl2 + H2O + CO2 In words, two moles of hydrochloric acid reacts with one mole of calcium carbonate to yield one mole of calcium chloride, one mole of water, and one mole of carbon dioxide.
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of oxygen are in one mole of calcium carbonate?
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
How many grams of calcium in 34.5 of Ca CO 3?
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
How many Ca atoms are found in 0.50 moles of CaCO3?
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
How many o atoms are present in 50gram of caco3?
50 grams CaCO3 (1 mole CaCO3/100.09 grams)(6.022 X 1023/1 mole CaCO3) = 3.0 X 1023 atoms of calcium carbonate =============================
How many moles of carbon are in 3.5 moles of calcium carbonate?
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
How much CaCO3 could be decomposed by 90 000 kj of heat energy?
delta H = (delta Ho f products) - (delta Ho f reactants) = ((1 mole CaO)(-636.6 kJ/mole) + (1 mole CO2)(-393.5 kJ/mole)) - (1 mole CaCO3)(-1206.9 kJ/mole) = -1030.1 kJ - (-1206.9 kJ) = +176.8 kJ This reaction is highly endothermic (positive delta H) at 25 C.
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
Calculate the number of mole of CO2 generated by the reaction of caco3 equals cao plus CO2 when 500 g cao is produce?
The decomposition reaction of calcium carbonate produces calcium oxide and carbon dioxide in a one to one ratio. 500 grams of CaO is 8.92 moles, so 8.92 moles of carbon dioxide are produced.
How many grams of calcium carbonate are needed to produce 93.0 L of carbon dioxide at STP?
At STP one mole of any gas occupies 22.4 L. The equation for the reaction is CaCO3(S) - -> CaO (s) + CO2 (g). Moles of CO2 in 93.0 L is 93/22.4 = 4.15 moles, the ratio of moles of CaCO3 and CO2 is 1:1, therefore 4.15 moles of CaCO3 will be required. 1 mole of CaCO3 is equal to 100.087 g/mol. Therefore, 4 .15 moles will have 415.2 grams.
Write a Balanced equation between HCl and CaCO3?
2 HCl + CaCO3 -> CaCl2 + H2O + CO2 In words, two moles of hydrochloric acid reacts with one mole of calcium carbonate to yield one mole of calcium chloride, one mole of water, and one mole of carbon dioxide.
When a 1.25-gram sample of limestone was dissolved in acid 0.44 gram of CO2 was generated if the rock contained no carbonate other than CaCO3 what was the percent of CaCO3 by mass in the limestone?
CaCO3 +2HCl ------------> CaCl2 + CO2 + H2O number of moles of CO2 in .44 grams = .44/ 44 = .01 From equation it is clear that 1 mole of CO2 is produced from CaCO3 = 1 mole .01 mole of CO2 is formed from CaCO3 = .01 mole Weight of .01 mole of CaCO3 is = .01mole *100 g/mole = 1 gram weight % of CaCO3 is = 1*100/ 1.25 = 80 % w/w I've post my answer, so why don't you show that answer here with the question. It's fare. I must be informed about my answer weather it is right or wrong. Please inform me at amitmahalwar@yahoo.com
