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1 mole F atoms = 6.022 x 1023 F atoms
1.01 x 1023 F atoms x (1mol F atoms/6.022 x 1023 Fe atoms) = 0.168mol Fe
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How many moles of fluorine in 3 moles of borontrifluoride?
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
How many moles are in 45g of F?
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
How many other pairs of atoms can carbon share its electrons with?
a carbon atom can share electrons with up to four other atoms.
A compound containing selenium and fluorine is decomposed in the laboratory and produces 2.231 of selenium and 3.221 of fluorinCalculate the empirical formula of the compound e?
The answer is SeF6.This is figured by:2.231 grams of Se divided by 78.79 g/mol = 0.0283 moles of Se3.221 grams of F divided by 18.998 g/mol = 0.1695 moles of F0.1695 moles of Se/0.0283 moles of F = 5.9909 ~ 6 moles of Se/mole of FSo SeF6
Why it takes less energy to release Cl atoms than F atoms from CFCs?
C-Cl bonds are easier to break than C-F bonds.
How many moles of molecules are there in 38g of fluorine F2?
The answer is two moles of F atoms or 1 mole of F2 molecules.
How many moles are in 1.16 1023 F atoms?
Approx. 0,1 mole F2 (o,2 mole as F).
What is the mass of 4 moles of fluorine atoms?
The mass of 4 moles of fluorine F atoms is 151,98 g (because fluorine is a diatomic element).
What is the mass in grams for 3.011 X 10 23 atoms F?
1 mole of any element is its atomic weight (from the periodic table) in grams.1 mole of atoms of an element is 6.022 x 1023 atoms (Avogadro's number).1 mole F = 18.9984032g F1 mole F = 6.022 x 1023 atoms FConvert atoms of F to moles F.3.011 x 1023 atoms F x (1mole F/6.022 x 1023 atoms F) = 0.5000 mole FConvert moles F to g F.0.5000 mole F x (18.9984032g F/1mole F) = 9.499g Fe
How many moles in 76 grams of fluorine?
(76 g F) * (1mol F/ 19g F) = 4 moles of F
How many atoms are present in 4.0 moles?
each mole has avogadro's number of atoms in it, which is 6.02 x 10 to the 23rd power. so, 4 x 6.02 x 10 23 power of atoms
What is the amount in moles of 1.50 x 1023 atoms F?
Amount of F atoms = (1.50x1023)/(6.02x1023) = 0.249mol Note: F in elemental form exists as diatomic F2 so the amount of fluorine gas would be 0.125mol.
How many atoms of fluorine are there in 2.5 mol?
1 mole F = 6.022 x 1023 atoms F 2.5mol F x 6.022 x 1023 atoms F/1mol F = 1.5 x 1024 atoms F
How many F atoms in 19g of CH2F2?
One mole of CH2F2 has a mass of (12.011)+2(1.0079)+2(18.9984) g = 52.0236 g 19 g of CH2F2 is equivalent to 19/52.0236 moles = 0.3652 moles For every mole of CH2F2 there are 2 F atoms, and 1 mole of a substance has 6.022 x 10^23 entities. So 19 g of CH2F2 has 2(0.3652)(6.022 x 10^23) F atoms = 4.40 x 10^23 F atoms.
How many moles of H2SO4 are needed to react with 2.4 moles of Aluminum metal?
0.8 moles Explanation: from the equation we can see, 2 mole A l is needed to react completely with 3 mole F e O so, 3 moles of F e O needs 2 moles A l so, 1 mole F e O needs 2 3 moles A l so, 1.2 mol F e O needs 2 × 1.2 3 moles A l = 0.8 moles A l
How many moles of fluorine in 3 moles of borontrifluoride?
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?
2.67 g NF3 x 1 mole NF3/71 g NF3 x 3 mole F/mole NF3 = 0.113 moles Fluorine
