735 g of Ca3(PO4)2 are obtained.
The answer is 0,4 moles.
978 g calcium contain 24,4 moles.
14,84 g magnesium are equivalent to 0,61 moles.
67,4 g HCl is equivalent to 1,85 moles.
735 g of Ca3(PO4)2 are obtained.
Molecular weight of CaNO32 is 164 grams/mol, so the answer is 106.6 grams
Molar mass of CaCO3 = 100.0869 g/molMolar mass of CaNO32 = 566.0655 g/mol
M.W. of the given compound is 3x23+1x31+4x16=164 in Na3PO4 3 moles of Na+ ions are produces i.e., 1mole weighs 164g contain 3x6.023x10^23 Na+ ions ?5.43g contain = 5.43g x 3 moles Na+ x 6.023x10^23 / 164 g/mol Na+ ions=0.598x10^23
3,80 g Zn have 0,058 moles.
The formula is: number of moles = g Be/9,012.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The answer is 0,364 moles.
The answer is 0,4 moles.
The answer is 0,253 moles.
978 g calcium contain 24,4 moles.
14,84 g magnesium are equivalent to 0,61 moles.