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H molar mass = 1.0 x 2(for two atoms H per molecule)
S molar mass = 32.1 x 1(only one atom S per molecule)
O molar mass = 16.0 x 4(for four atoms O per molecule)
(1.0 x 2) + (32.1 x 1) + (16 x 4) = 98.1 g/mol
36 g x 1 mol/98.1 g = 0.37 mol
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How many molecusles are contained in 55.0 g of H2SO4?
how many molecules are containd in 55.0g of H2SO4
What is the mass of oxygen in 250 g of sulfuric acid H2SO4?
The mass of 2,25 moles of sulfuric acid H2SO4 is 220,677 g.
How many moles are in 0.50 of H2SO4?
Did you mean 0.5 g? or mg? or ml?Anyway, amount of substance in moles is calculated as m/Mwhere m is mass and M is molal mass.M (H2SO4) is 1*2 + 32 + 16*4 = 98 g/mole
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
How many moles are there in 98.1 g of H2SO4?
1 mole Since H2SO4's molar mass is 98.1g, and a substance's molar mass contains exactly 1 mole, that is the answer
How many moles are there in 22.4 g of H2SO4?
22.4g/98.09 g/mol = 0.228mol
How many molecusles are contained in 55.0 g of H2SO4?
how many molecules are containd in 55.0g of H2SO4
What is the mass of oxygen in 250 g of sulfuric acid H2SO4?
The mass of 2,25 moles of sulfuric acid H2SO4 is 220,677 g.
How many moles are in 0.50 of H2SO4?
Did you mean 0.5 g? or mg? or ml?Anyway, amount of substance in moles is calculated as m/Mwhere m is mass and M is molal mass.M (H2SO4) is 1*2 + 32 + 16*4 = 98 g/mole
What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4?
The answer is 0,526 mL.
How many moles are there in 98.1 g of H2SO4?
1 mole Since H2SO4's molar mass is 98.1g, and a substance's molar mass contains exactly 1 mole, that is the answer
How many liters of a 4 molar solution of H2SO4 is needed to provide 100 g of H2SO4?
Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
How many grams are in 0.50 mol H2SO4?
The weight of 2,5 mol of sulfuric acid is 245,1975 g.
How many milliliters of 3.0 m h2so4 are required to react with 0.80 g of cuo in the equation cuo h2so4 cuso4 H2O?
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
How many grams are in 2.5 moles of sulfuric acid?
The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.
What is the mass in moles of 16.4 mL H2SO4 solution d equals 1.727 gmL 80.0 percent H2SO4 by mass?
The answer is 20,5 g or 0,209 mol.
How many moles of oxygen are needed to react completely with 2.3 moles of H2S 2H2S plus 3O2 2SO2 plus 2H2O?
H2S (g) + 2 O2 (g) --> H2SO4 (l) 1 mole + 2 mole --> 1 mole You will need 2 moles of O2
