For this you need the Atomic Mass of Al. Take the number of grams and divide it by the atomic mass. Multiply it by one mole for units to cancel.
94.5 grams Al / (27.0 grams) = 3.50 moles Al
There are 26.98 gram in 1 mole Al, so it is 1/26.98 = 0.03706 mole per gram Aluminum
1 mole of Al is equal to about 27 grams (Periodic Table).
Use this as a conversion factor.
4,25 moles of aluminium is equivalent to 114,67 g.
moles of Al = 97.6 g Al x 1 mol Al/26.98 g Al = 3.62 moles Al (3 sig figs)
1/27 = 0.037
The answer is 0,07 moles.
One mole weights 26.98 grams, so it is arouind 27 g. So 4 moles weight almost 108 grams.
1 mole Al(CN)3 = 105.03g _ moles = 163g 1 mole Al(CN)3 * 163g / 105.03g 163 moles/105.03 = 1.55 moles
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
9.55 mol of Al
find moles: 20.0 grams of Al @ (27.0 g/mol) = 0.7407 moles of Al by the reaction: 2 moles Al+3CuSO4 → Al2(SO4)3 +3 moles Cu 0.7407 moles of Al produces 3/2 's as many moles of Cu = 1.11 moles of Cu find mass, using molar mass: 1.11 moles of Cu @ (63.5 g/mol) = 70.6 grams of Cu your answer is 70.6 g
1mol Al = 26.981538g Al1mol Al atoms = 6.022 x 1023 atomsConvert grams to moles.1g Al x 1mol/26.981538g = 0.04mol AlConvert moles to atoms.0.04mol Al x 6.022 x 1023 atoms/mol = 2 x 1022 atoms Al
Equation. 2Al + 3Cl2 -> 2AlCl3 one to one again 0.440 moles Al (2 moles AlCl3/2 moles Al) = 0.440 moles AlCl3 produced
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
One mole weights 26.98 grams, so it is arouind 27 g. So 4 moles weight almost 108 grams.
1 mole Al(CN)3 = 105.03g _ moles = 163g 1 mole Al(CN)3 * 163g / 105.03g 163 moles/105.03 = 1.55 moles
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
The answer is 3,375 moles oxygen.
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.91 moles Al × (27.0 grams) = 78.6 grams Al
9.55 mol of Al
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.