NaOH is 40 molecular weight, so 4g means there is 0.1 moles present.
The answer is 0,111 moles.
3,5 moles of sodium oxide will be produced when 10 moles of sodium reacts with oxygen.
The answer is 0,017 moles.
The answer is 8,559.10-5 moles.
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
The formula mass of sodium carbonate, Na2CO3 is 2(23.0)+12+3(16) = 106.0Amount of sodium carbonate = mass of sample / formula mass = 4/106.0 = 0.0377mol
there are 4.5 moles
How many formula units of sodium acetate are in 0.87 moles of sodium acetat
Sodium in its elemental form is just sodium metal, Na. Thus assuming that the sample of sodium is pure, there are 2.50 moles of sodium in a 2.50mol sample.
5,25 moles (in anhydrous sodium sulphate)
5,75 g of sodium is equal to 0,25 moles.
6,5 g sodium is equivalent to 0,283 moles.
There are two moles of sodium ions in two moles of sodium chloride.
The answer is 0,175 moles.
The reaction equation is 2 Na + O2 -> Na2O. this shows that each mole of sodium oxide requires two moles of sodium. Therefore, 5 moles of sodium oxide will be produced by reacting 10 moles of sodium.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
3.55 moles of sodium is equivalent to 21,3781.10e23 atoms.
55.0 moles of sodium are equal to 1 264,44 g.
4,0g of sodium hydroxide is equivalent to 0,1 moles.
The answer is 5,2197.
Atomic Weight sodium = 23 so 46/23 = 2 moles of sodium in 46.0g