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For this you need the atomic (molecular) mass of Fe2(SO4)3. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. Fe2(SO4)3=400.1 grams

768 grams Fe2(SO4)3 / (400.1 grams) = 1.92 moles Fe2(SO4)3

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15y ago
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14y ago

1 mole of Fe2O3 contains 159.6 grams. So 7.86 moles contain 1254.456 grams of Fe2O3.

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11y ago

183 grams Fe2O3 (1 mole Fe2O3/159.7 grams)

= 1.15 moles of ferric oxide

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Q: How many moles are in 182.7 g Fe?
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