For this you need the atomic (molecular) mass of Fe2(SO4)3. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. Fe2(SO4)3=400.1 grams
768 grams Fe2(SO4)3 / (400.1 grams) = 1.92 moles Fe2(SO4)3
1 mole of Fe2O3 contains 159.6 grams. So 7.86 moles contain 1254.456 grams of Fe2O3.
183 grams Fe2O3 (1 mole Fe2O3/159.7 grams)
= 1.15 moles of ferric oxide
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233,2 g iron Feis equivalent to 4,176 moles.
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
This amount may be different because rust is not a clearly definite compound.
The answer is 0,4 moles.
978 g calcium contain 24,4 moles.
4 moles - APEX
233,2 g iron Feis equivalent to 4,176 moles.
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe
The answer is 125,65 g.
This amount may be different because rust is not a clearly definite compound.
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
388.grams Fe divided by mass of Fe 388.2g/55.85= 6.95moles of Fe
Fe(NO3)2molecular weight. Molar mass of Fe(NO3)2= 179.8548 g/mol. This compound is also known as Iron(II) Nitrate. Convert grams Fe(NO3)2to moles or moles Fe(NO3)2to grams.
Depict moles eg: Fe2O3(s) + 3CO(g)--> 2Fe(s) + 3CO2(g) 1 mole of Fe2O3 4 moles of CO 2 moles of Fe 3 moles of CO2
3.0 g Fe x 1 mole Fe/55.8 g = 0.054 moles Fe2.0 g S x 1 mole S/32 g = 0.063 moles STherefore there are more molecules of S than of Fe since one mole of either = 6.02x10^23 atoms.
Fe, or iron, has a molar mass of 55.845 grams per mole. This means that 0.2 moles is equal to 11.2 grams of iron.