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How many moles of nitrate ions are there in 2 oles of magnesium nitrate?
There are 6 moles of nitrate ions in 2 moles of magnesium nitrate. This is because there are 3 nitrate ions (NO3-) in each formula unit of magnesium nitrate (Mg(NO3)2). So, 2 moles of Mg(NO3)2 would contain 6 moles of nitrate ions.
How many moles of magnesium nitrate are produced when magnesium reacts with 8 moles of nitric acid?
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
How many grams are in 88.1 moles of magnesium?
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
How many moles in 4.50 grams of silver nitrate?
To find the number of moles in 4.50 grams of silver nitrate (AgNO3), you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Then, use the formula: moles = mass/molar mass. So, 4.50 grams of AgNO3 is equal to 0.0265 moles.
How many moles of lithuim nitrate are produced wh en3.00 moles of iron 3 nitrate react?
When 3.00 moles of iron (III) nitrate react, they will produce an equal number of moles of lithium nitrate, according to the balanced chemical equation. So, 3.00 moles of lithium nitrate will be produced.
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many moles of nitrate ions are there in 2 oles of magnesium nitrate?
There are 6 moles of nitrate ions in 2 moles of magnesium nitrate. This is because there are 3 nitrate ions (NO3-) in each formula unit of magnesium nitrate (Mg(NO3)2). So, 2 moles of Mg(NO3)2 would contain 6 moles of nitrate ions.
How many grams are in 1.11 moles of magnesium?
1,11 moles of magnesium have 26,97855 g.
How many moles of magnesium nitrate are produced when magnesium reacts with 8 moles of nitric acid?
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.
How many moles are in 88.1 grams of magnesium?
88,1 moles of magnesium is equivalent to 2 141,27 g.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
How many grams are in 3.5 moles tin iv nitrate?
15.451
How many moles in 1.25 grams of iron nitrate?
To find the number of moles in 1.25 grams of iron nitrate, we need to know its molar mass. Iron nitrate has a molar mass of approximately 404.0 g/mol. By dividing the mass by the molar mass, we find that 1.25 grams of iron nitrate is roughly 0.0031 moles.
How many grams are in 5.2 moles of magnesium sulfide?
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
How many grams are in 88.1 moles of magnesium?
If you think to the mass of 88,1 moles of magnesium this is 2141,27 g.
How many moles of nitrate ion are present in 5.600grams of calcium nitrate?
To find the number of moles of nitrate ion in calcium nitrate, first calculate the molar mass of calcium nitrate (Ca(NO3)2). This is 164.09 g/mol. Divide the given mass (5.600 g) by the molar mass to get the number of moles, which is 0.034 moles. Since there are two nitrate ions in one calcium nitrate molecule, multiply the number of moles by 2 to get the number of moles of nitrate ions, which is 0.068 moles.
How many moles are in 13.2 grams of magnesium?
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Mg= 24.3 grams35.0 grams Mg / (24.3 grams) = 1.44 moles Mg
