Chemistry
Molecular Mass

# How many moles in 20 grams of Na2CO3?

20 g anhydrous sodium carbonate is equivalent to 0,188 moles.

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molar mass Na2CO3 = 106 g/mol
20 g x 1 mol/106 g = 0.189 moles = 0.19 moles (to 2 significant figures)

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## Related Questions

Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------

There are 0.13 moles in 20 grams of magnesium nitrate.

the density of Na2Co3 is about 2.54 g/cm3. so, the mass of it would be about 2.54*20=50.8 g. 50.4 divided 6.23*1023 equals to 8.08*10-23 mol

1 mole He = 4 g He 5 moles of He = 20 g of He

Moles = mass / relative molecular mass. 360 / 1 + 1 + 16 = 20 moles

Can find moles this way. Molarity = moles of solute/Liters of solution ( 500 ml = 0.500 Liters ) 1 M NaOH = moles NaOH/0.500 Liters = 0.5 moles NaOH (39.998 grams/1 mole NaOH) = 19.999 grams NaOH needed ( call it 20 grams )

20 grams of NaOH contains 0.5 moles of the compound.

801 g Ca * (1 mole Ca/40.08 g Ca) = 19.985 moles There are about 20 moles of calcium atoms in 801 grams of calcium

mass divided by molar mass gives moles: 20 g NaOH / 40 g.mol-1 = 0.5 mol NaOH

No of moles= given mass/molecular mass = 600/30= 20 moles

The answer is in the question. There are 20,000 grams in 20 kilograms.

Four teaspoons in 20 grams 1 TSP = 5 grams

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