The formula weight of NaCl is 58.44 which means 58.44 g = 1 mole.
Since 1000 mg = 1 g, this gives
58.44 g/mole x 1000 mg/g = 5.844 E+4 mg/mole.
Then, 52.1 mg NaCl x 1 mole NaCl/5.844E+4 mg = 8.92 E-4 mole.
See, this is just done by using the definitions of the units and the factor label method to analyze the conversion.
The answer is 4,466 moles.
1 mole
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
1 mole of NaCl: Na = 1 * 22.99 g = 22.99 g Cl = 1* 35.45 g = 35.45 g Total = 58.44 g 238 g NaCl * (1 mol NaCl/58.44 g NaCl) = 4.07 mol NaCl There are approximately 4.1 moles in 238 grams of sodium chloride.
The answer is 0,96 moles.
Balanced equation first. NaOH + HCl >> NaCl + H2O Everything is one to one, so 1.222 moles HCl (1mole NaOH/1mole HCl) = 1.222 moles NaOH
How many moles is in 0.0688 Ag Cl
1 mole NaCl = 58.443g NaCl 234g NaCl x 1mol NaCl/58.443g NaCl = 4.00 moles NaCl
Every mol of NaCl contains a mol of Na, weighting 23 grams, and a mol of Cl, weighing 35.5 grams. So, every mol of NaCl weights 58,5 (=23+35.5) grams. Therefore, 145 moles of NaCl weights 8482.5 grams.
The answer is 7,73 moles.
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
50 g of NaCl represent 0,856 moles.