Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
There are 1.5 moles water in 27 grams
2.08 moles H2O (2 moles H/1 mole H2O)(1.008 grams H/1 mole H) = 4.19 grams of hydrogen ===================
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
8g / 18 g/mol H2O = .44 moles H2O
The answer is 8,33 moles.
H2O or water doesn't have any helium in it.
Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
There are 1.5 moles water in 27 grams
The answer is 0,44 moles.
2.08 moles H2O (2 moles H/1 mole H2O)(1.008 grams H/1 mole H) = 4.19 grams of hydrogen ===================
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
8g / 18 g/mol H2O = .44 moles H2O
3.0 moles of H2O have 54 g.
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
It forms H2O when burned.There are 3.744 moles of H2O after burned.
2H2 + O2 --> 2H2OFor every 2 moles of H2, 2 moles of H2O will be produced (i.e., a 1:1 ratio). So to produce 8.25 moles of H2O you will also need 8.25 moles of H2