.0150 mol
200/1000 x 6 = 1.2 moles
You have 2 litres. You need to divide 91 by 2 to get it per litre. 91/2 is 45.5g. 45.5 / 95.211. This gives you 0.477886 molar
So molarity means moles per litre. but you don't have a litre. if you did you'd have 1000/200 times the moles that you have. 2 moles / 200 x 1000 is 10 moles. As it is per litre, it is 2 molar.
200 mL is 0.200 L and 0.90 M means 0.90 moles/L So, 0.200 L x 0.90 moles/L = 0.18 moles
200g times 342.2965 g/mol = 68459.3 moles
200/1000 x 6 = 1.2 moles
The molecular weight of Calcium Bromide is extremely close to 200. So 1200/200 = 6 moles present.
You have 2 litres. You need to divide 91 by 2 to get it per litre. 91/2 is 45.5g. 45.5 / 95.211. This gives you 0.477886 molar
So molarity means moles per litre. but you don't have a litre. if you did you'd have 1000/200 times the moles that you have. 2 moles / 200 x 1000 is 10 moles. As it is per litre, it is 2 molar.
200 mL is 0.200 L and 0.90 M means 0.90 moles/L So, 0.200 L x 0.90 moles/L = 0.18 moles
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200g times 342.2965 g/mol = 68459.3 moles
200
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.
To determine the number of moles of ions present in a known volume of solution, follow this example:HCl dissociates completely in water into H+ and Cl-, because this is a strong acid, and only strong acids, bases, and ionic compounds have the ability to dissociate completely.This means one equivalent of HCl will generate one equivalent of H+ and Cl- ions; the same number of moles of HCl will generate the same number of moles for H+ and Cl-HCl --> H+ + Cl-Now determine the number of moles in the volume of your solution. Remember that 1M is another way to say 1 mole/L.(2moles HCl/ 1L) x (1L) = 2 moles HClSince the equation states that 1 equivalent of HCl is 1 H+, the final answer is:(2moles HCl/ 1L) x (1L) x (1 mole H+/1mole HCl) = 2 moles H+
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