6,022 x 1023 atoms/mole. Calcium nitrate = Ca(NO3)2 .There are 1 mole of calcium making 6,022 x 1023 atoms of calcium.There are 2 moles of nitrate-ions and each nitrate-ion is made up of 1 mole nitrogen, and 3 moles of oxygen. Thath means that the nitrate ion in calcium nitrate has 6 moles oxygen and 2 moles of nitrate:Atoms of nitrogen: 6,022 x 1023 moles-1 x 2 moles = 1,2044 x 1024 atomsAtoms of oxygen: 6,022 x 1023 moles-1 x 6 moles = 3,6132 x 1024 atoms
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
1 kg of difluorodichloromethane is equivalent to 8,27 moles.
As shown by the ionic equation of the reaction, Zn (s) + 2 Ag+ (aq) --> 2 Ag (s) + Zn2+ (aq), each mole of zinc produces two moles of silver. Therefore, 1.30 moles of zinc will displace 2.60 moles of silver.
The equivalent of 125 g zinc is 1, 91 moles.
The volume occupied by 3 moles of nitrogen gas will be different, depending on the temperature and pressure of the gas.
For clarity, zinc (II) nitrate would be the preferred name. However, if you just said "zinc nitrate", most chemists would guess you meant that formula; the +1 oxidation state is technically possible for zinc, but zinc (I) compounds are relatively rare.
Since both chloride anions and nitrate anions have a charge of -1, there will be the same number of moles of silver chloride produced as the moles of silver nitrate reacted. (Since both silver nitrate and silver chloride are ionic compounds, it would be preferable to call their "moles" "formula units" instead.)
6,022 x 1023 atoms/mole. Calcium nitrate = Ca(NO3)2 .There are 1 mole of calcium making 6,022 x 1023 atoms of calcium.There are 2 moles of nitrate-ions and each nitrate-ion is made up of 1 mole nitrogen, and 3 moles of oxygen. Thath means that the nitrate ion in calcium nitrate has 6 moles oxygen and 2 moles of nitrate:Atoms of nitrogen: 6,022 x 1023 moles-1 x 2 moles = 1,2044 x 1024 atomsAtoms of oxygen: 6,022 x 1023 moles-1 x 6 moles = 3,6132 x 1024 atoms
4.50 g(1/169.88) =.0265 mols
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
Zinc nitrate ( Zn(NO3)2) has the elements, zinc, nitrogen and oxygen.
6,022140857.10e23--------------1 mol1,33.10e24----------------------------xx = 1,33.10e24/6,022140857.10e23 = 2,2 moles Zn
Zn + H2SO4 ---> ZnSO 4 + H2 so one mole of zinc and 1 mole of sulfuric acid produces one mole of hydrogen molecules and thus two moles of hydrogen atoms. So 0.36 moles of zinc will produce 0.36 moles of hydrogen molecules and thus 0.72 moles of hydrogen atoms.
Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g) since the only mole value given is 8 I must assume this is the limiting reactant. Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.