methane has one carbon atom and 4 hydrogen atom.....so one mole of methane contains one mole of carbon and 4 moles of hydroge......for simplicity...one mole of water has two moles of hydrogen and one mole of oxygen....
Ethane has the formula CH3CH3. So, each mole of ethane contains 6 moles of H.13.78 moles ethane x 6 moles H/mole ethane = 82.68 moles H.
If the question is asking how many moles of hydrogen GAS are needed, then the answer is 1/2 of 82.68 since hydrogen gas is H2.
There are 6 hydrogen atoms in every molecule of ethanol.
Molecular formula of ethene: C2H4 or CH2=CH2
Therefore an ethene molecule contains FOUR hydrogen atoms.
The chemical formula for ethanol is C2H6O, or C2H5OH. One mole of ethanol has six moles of H atoms.
Six
27.56 mol
3.445 mol
This is based on calculations too. It contains 18 hydrogen moles.
The needed mass of sodium is 91,659 g (for 2 moles H2).
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
1 mole of carbon monoxide and 2 moles of diatomic hydrogen.
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
The answer is 97,66 moles.
This is based on calculations too. It contains 18 hydrogen moles.
Approx. 4 moles.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
The needed mass of sodium is 91,659 g (for 2 moles H2).
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
1 mole of carbon monoxide and 2 moles of diatomic hydrogen.
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
3,75 moles hydrogen
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
This is not a common reaction at standard temperature and pressure.