For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.17.5 grams Na / (23.0 grams) = .761 moles Na
atomic waight of hydrogen = 1.0079 weight of one mole of hydrogen = its atomic mass in grams(just like all elements). therefore 454g/1.0079g = 450.4 moles of hydrogen.
1 mole Na = 22.989770g 10 moles Na = 10 x 22.989770g = 229.89770g
11.5 g of Na times x (1 mole of Na/22.99 g of Na) = 0.500 mol of Na I suppose the conversion factor would be what's in parenthesis.
Atomic mass of Na is 23.0. This means that the mass of 1 mole of sodium is 23.0g. Mass of 4.5mol of Na = 4.5 x 23.0 = 103.5g
The answer is 0,25 moles.
22.98977 grams.
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.17.5 grams Na / (23.0 grams) = .761 moles Na
0.21705 moles. There are 22.9898 grams sodium in 1 mole.
None. There is no hydrogen in sodium
40*4=160g
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
Mass of 2 moles of Na = 2 x atomic mass of Na = 2 x 23.0 = 46.0g
2 mol x 22.99 g Na= 45.98 g Na
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
atomic waight of hydrogen = 1.0079 weight of one mole of hydrogen = its atomic mass in grams(just like all elements). therefore 454g/1.0079g = 450.4 moles of hydrogen.