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There are 10 electrons per molecule of NH3,17g of ammonia means one mole, therefore 10 moles of electrons are present.

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Q: How many moles of electrons are present in 17 grams of ammonia?
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If formula for ammonia is NH what is the mass of 3 moles of ammonia would be in grams?

The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.


The mass of 3 moles of ammonia would be how many grams?

3 moles of ammonia is 51grams. One mole is 17 grams.


The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?

The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.


Mass of 3 moles of ammonia would be?

The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.


How many moles of ammonia is 170000g?

Ammonia = NH3Molecular mass = 16.0Formula of grams to moles: grams / molecular mass = moles170,000 g / (16.0) = 10,600 moles NH3Note that the answer is with three significant digits


How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?

0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.


How many moles are in 12 x 10.3 grams of ammonia NH3?

Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.


What is the mass of 10 moles of ammonia given that molecular weight is 17?

If ammonia (NH3) has a molar weight of 17 grams per mole, then 10 moles means 17x10=170 grams.


How many moles are present in 1g of ammonia?

5.8x10^-2


How many MOLES of sodium nitrate are present in 2.85 grams of this compound?

How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?


How many moles of ammonia are needed to produce 3.5 mole of nitrogen?

That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.


How many moles are in 1.2 X 10.3 grams of ammonia NH2?

Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.