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Q: How many moles of phosphorus atoms are in 100 grams of P4S10?
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How many moles of phosphorus are in 392 grams of phosphorus?

Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================


How many moles are in 2.3 grams of phosphorus using avogadro's number?

2.3 grams P (1mole P/30.97 grams) = 0.07427 moles Phosphorous 0.07427 moles P * 6.022 X 10^23 = 4.5 X 10^22 atoms of P in 2.3 grams P 4.5 X 10^22/6.022 X10^23 = 0.07427 moles of atoms in 2.3 grams of phosphorous


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The number of phosphorus atoms is 63,181.10e23.


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How many grams of phosphorus trichloride are present in 3.42 moles of this compound?

3,42 moles of phosphorus trichloride have 469,6686 g.


How many moles of phosphorus atoms are there in 8 moles of P4O10?

Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus


How to convert grams to atoms?

To convert grams into atoms, you have to convert them into moles first. Get the molar mass and multiply it by the number of moles to get the atoms.


How many moles of phosphorus atoms are in a 100 g sample of phosphorus?

The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.


How many grams of phosphorus are present in 4.70 moles of tetraphosphorus decaoxide?

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