For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. CO2=44.0 grams
454 grams CO2 / (44.0 grams) = 10.3 moles CO2
The gram molecular mass of carbon dioxide is 44.01. Therefore, 454 grams constitutes (454/44.01) or 10.3 moles, to the justified number of significant digits.
5.77 moles
look its easy. if you have X moles of Ca you would look it up in the elements chart and figure it out right? now all you have to do is figure out how many moles do you get of each element in the compound above and sum them up. if it still doesnt help post on my message bourd ok?
You would take your grams divided by the FW (formula weight) of the molecule. example: 1g of H2O divided by 18 = .056mol H2O you find the formula weight by adding of the atomic masses of each element O=16 and H=1 1(2)+16=18
just short of a mole. moles is mass/molar mass. mass is 42, molar mass is 44. 42/44
One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.So you take 12 and multiply it with 6.02 × 1023 to get 7.22 × 1024
To convert the mass of a carbon dioxide to moles takes two steps. First, sum the molecular weights of carbon and oxygen (oxygen's atomic weight is added twice because there are two oxygen atoms in the molecule). Then, simply divide the mass by the number calculated. The result is the number of moles of CO2
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2= 44.0 grams1.50 moles CO2 × (44.0 grams) = 66.0 grams CO2
For this you need the atomic (molecular) mass of CO2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CO2=44.0 grams2.00 moles CO2 × (44.0 grams) = 88.0 grams CO2
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
6.5 grams CO2 divided by 44 grams CO2 per mole CO2 = 6.8 mole CO2 (Molar mass CO2 = 12 + 2*16 = 44 g/mol)
C + O2 = CO2 So the theoretical number of moles are 1 each. number of moles is mass/molecular weight C = 6/12 which is 0.5 O2 = 11/32 which is 0.34375 Oxygen is the limiting reagent. So 0.34375 moles is reacted and this also gives 0.34375 moles CO2 no moles is mass over molecular mass grams is moles x molec mass 0.34375 x 44 = 15.125 grams CO2 formed. learn the technique. this is needed in science
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams33.0 grams C / (44.0 grams) = .750 moles CO2
44.01
First write the balance equation: Na2CO3 + 2HNO3 ==> 2NaNO3 + CO2 + H2O Next calculate moles of Na2CO3 used: 7.5 g x 1 mole/106 g = 0.071 moles Na2CO3 Then look at mole ratio of Na2CO3 to CO2 and see that it is 1 to 1 Thus, moles CO2 produced = 0.071 moles Finally, convert moles CO2 to grams of CO2: 0.071 moles x 44g/mole = 3.1 g (to 2 significant figures)
The answer is 3,99 moles of carbon dioxide.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
The answer is 3,99 moles of carbon dioxide.