40 ml of NaOH contains 0.04 L * 3.5 M = 0.14 mole of NaOH
Since NaOH donates 1 OH you will also have 0.14 mole of OH- in solution.
This can be neutralised with an equal amount of H+.
HCl can donate 1 H+, so you need an equal amount of H+ to neutralise the OH-.
So you need 0.14 mole of the HCl.
55 ml has 0.14 mole HCl.
So the molarity is: 0.14 mole / 0.055 L = 2.54 M
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
This sodium hydroxide solution has a molarity of 0,25.
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
The molarity is 0,33.
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
The answer is 0,625 moles.
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
This sodium hydroxide solution has a molarity of 0,25.
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
The molarity is 0,33.
The molarity is 0,2.
67
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
0.289 Moles is the molarity of an NaOH solution if 4.37 ml is titrated by 11.1 ml of 0.0904m hno3.
Molarity = moles of solute/volume of solution 0.53 M NaOH = moles NaOH/3.8 Liters = 2.014 moles, or about 80 grams