67
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
Molarity is per litre. So whatever you do to convert the volume back to per litre you have to do to the moles. 2.5/500, x1000 is 5 molar.
Molar mass of HNO3 =63g Given mass= 12.6g No. of moles=12.6/63=0.2 moles Molarity= No. of moles/Volume of solution(in litre) = 0.2/0.5=0.4 M
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
675
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
6 molar
Molarity is per litre. So whatever you do to convert the volume back to per litre you have to do to the moles. 2.5/500, x1000 is 5 molar.
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
Molar mass of HNO3 =63g Given mass= 12.6g No. of moles=12.6/63=0.2 moles Molarity= No. of moles/Volume of solution(in litre) = 0.2/0.5=0.4 M
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
675
To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.
A 0.205 M solution will have 0.205 moles per liter. 250 milliliters is 1/4 of a liter, so in that sample, there will be 0.05125 moles. NaOH has a molar mass of 39.9971 grams per mole, so 2.05 grams added to 250 mL of water will make the desired solution.
8000-500=7500.
500