First you have to balance the equation
N2 + H2 ---> NH3
N2 +3H2 ---> 2NH3
Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
(34 g NH3) x (14 g N ) / (17 g NH3) = 28 g N(28 g N) x (1 g N) / (2 g N2) = 14 g N2
Assuming you mean the decomposition of ammonia: 2NH3 --> N2 + 3H2, 100g NH3 = 5.88mol (100/17), and the ratio of ammonia to nitrogen is 2:1. 5.88mol/2=2.94mol, so that's the amount of nitrogen produced. 2.94x28 (molar mass of N2) gets you 82.3g nitrogen produced.
You are probably asking about the molar mass of NH3. This is a measure of the amount of grams in one mole of NH3. This can be found by adding the molar masses of each element. Also, you must be sure to multiply each molar mass of an element by the number of atoms of that element that are present. In NH3 there is one nitrogen atom and 3 hydrogen atoms. Nitrogen has a molar mass of 14.01 and Hydrogen has a molar mass of 1.008. Therefore: 1*(14.01) + 3*(1.008) = 17.034 So for every mole of NH3 you will have 17.034 grams.
Ammonia = NH3 and has a molar mass of 17.031 g/molmoles NH3 = 63.9 g x 1 mol/17.031 g = 3.752 molesmolecules NH3 = 3.752 moles x 6.02x10^23 molecules/mole = 2.259x10^24 moleculesEach molecule of NH3 has 4 atoms (1 N + 3 H), thus....number of atoms = 4 atoms/molecule x 2.259x10^24 molecules = 9.04x10^24 atoms (to 3 sig figs)
molar weight of N = 14 grams/mole 35.7 grams/14 grams/mole = 2.55 moles
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
(34 g NH3) x (14 g N ) / (17 g NH3) = 28 g N(28 g N) x (1 g N) / (2 g N2) = 14 g N2
0.545 * (14+1+1+1) 0.545 * ram n + 3 * ram h
The reaction equation is 8 F2 + 2 NH3 equals N2F4 + 6 HF2. So every mole of NH3 requires four moles of F2. This means 14 moles of F2 or 532 grams.
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.
14 grams of palm oil is about a half of an ounce if that helps.
It is 14 - 3 = 11 grams more massive.
75
14 grams
molar mass=NH314+3=17moles=give mass /molar mass400 / 17=23.5294