http://wiki.answers.com/Q/Is_duchenne_muscular_dystrophy_heterozygous_or_homozygous"
It is heterozygous.
Homozygous dominant (Ex:AA) Heterozygous (Ex:Aa) Homozygous recessive (Ex:aa)
Homozygous is the same(purbred) and heterozygous is different(hybrid)
heterozygous
The man has Huntington's disease
it is a homozygous or heterozygous ( RR or rr)
There only certain crosses that will produce heterozygous offspring. These are heterozygous vs heterozygous, homozygous vs homozygous and heterozygous vs homozygous.
heterozygous
50%
homozygous- TT; heterozygous- Tt :)
Homozygous dominant (Ex:AA) Heterozygous (Ex:Aa) Homozygous recessive (Ex:aa)
Heterozygous
Homozygous is the same(purbred) and heterozygous is different(hybrid)
Most patients are heterozygous for the mutant copy of huntingtin however in some rare cases there are individuals who are homozygous for the disease-causing allele. Homozygosity for the disease gene does NOT cause death at the embryo stage as the previous answer stated. Huntingtin null mice show embryonic lethality, but this is when they have no copies of the huntingtin gene at all. This is not the same as being mutant for the gene. Individuals will have received one copy of the huntingtin gene from each of their parents and so the number of disease-causing CAG repeats will vary between each allele. If both copies have more than 35 repeats then they can be said to be homozygous for the mutant huntingtin allele. This seems to result in more severe symptoms and disease progression.
homozygous
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
Yes - Hh is heterozygous. HH is homozygous, and hh is homozygous.
The homozygous dominant form is lethal, because it produces twice as much protein (HH = two doses of H) as Hh would. Only if you assume that the alleles for Huntingtons are co-dominant. According to an article called Homozygotes for Huntington Disease, 'the clinical expression of HD among homozygotes is not more severe than observed in heterozygotes.'