Want this question answered?
it's electron-withdrawing group.
Assuming the groups are conjugated to the acid/base groups: An acid wants to lose a proton. When it loses a proton, you form an anion (or a neutral molecule, but when talking about electron donating/withdrawing groups, you assume there is a charge). The more stable the anion, the more easily the proton comes off, and the more acidic it is. A base is the opposite. A base gains a proton to become cationic. The more stable the cation, the more likely it is to pick up a proton, and the more basic it is. An electron withdrawing group can stabilize an anion (and thus make something more acidic) and an electron donating group can stabilze a cation (and make something more basic). The opposites also hold true: an electron donating group can destabilize an anion and make something less acidic, and vice versa for bases.
yes it is
aniline is more acidic because in aniline a electron withdrawing benzene is connected.electron withdrawing capacity of benzene is due to its delocalizing pi electrons cloud.due the action of benzene the presence of unshared pair of electron over nitrogen is somehow decreases.which increases its acidic nature. But in case of ammonia there is no electron withdrawing group.so its unshared pair of electron remains undistrubed,which decreases its acidity and increases its basisity
The electron configuration for oxygen is [He]2s2.2p4.The electron configuration for sulfur is [Ne]3s2.3p4.
it's electron-withdrawing group.
"OH" group attached to aromatic ring is electrons donor because it has two lone pairs of electrons on oxygen atom which may involve in resonance process, but "OH" group attached to saturated carbon act as electrons attracting group due to high electronegativity of oxygen.
If the base hydrolysis mechanism is important, an electron withdrawing group can be attached to the prodrug. If the acid hydrolysis mechanism is important, an electron donating group can be attacked to the prodrug.
the halogens are electron withdrawing groups. e.g. F, Cl, etc
Assuming the groups are conjugated to the acid/base groups: An acid wants to lose a proton. When it loses a proton, you form an anion (or a neutral molecule, but when talking about electron donating/withdrawing groups, you assume there is a charge). The more stable the anion, the more easily the proton comes off, and the more acidic it is. A base is the opposite. A base gains a proton to become cationic. The more stable the cation, the more likely it is to pick up a proton, and the more basic it is. An electron withdrawing group can stabilize an anion (and thus make something more acidic) and an electron donating group can stabilze a cation (and make something more basic). The opposites also hold true: an electron donating group can destabilize an anion and make something less acidic, and vice versa for bases.
yes it is
no!
alcohols have methyl groups, ethyl groups ect... attached to the alcohol. Carbon and its hydrogens are considerd electron donating groups (because they are not electronegative like F, O or N); therefore they donate part of their electric charge toward the oxygen on the alcohol making that oxygen less able to distribute the electron from the lost hydrogen. Meanwhile, water can lose a hydrogen and does not contain any electron donating groups (such as Carbon) and the oxygen is better suited to distribute the extra electrons from the lost hydrogen. think about it... if carbon is donating part of its electrons to oxygen in an alcohol, there is less room for that oxygen to take on the electrons from a lost hydrogen vs water.
yes. it will
Beacuse ethanol has a CH3,CH2 group, which are electron donating group and decreases the acidity of the compound. Water on the other hand does not have any electron donating group.
aniline is more acidic because in aniline a electron withdrawing benzene is connected.electron withdrawing capacity of benzene is due to its delocalizing pi electrons cloud.due the action of benzene the presence of unshared pair of electron over nitrogen is somehow decreases.which increases its acidic nature. But in case of ammonia there is no electron withdrawing group.so its unshared pair of electron remains undistrubed,which decreases its acidity and increases its basisity
Cinnamon is 90% cinnamaldehyde. Cinnamaldehyde is an aldehyde and the carbonyl oxygen has significant electron withdrawing potential. So, it is polar. Link below to an electronic potential map of the molecule