the halogens are electron withdrawing groups. e.g. F, Cl, etc
the electron in benzene are delocalised making d ring to be elctron rich,thereby undergoing electrophilic substitution.benzene cannot undergo nucleophillic substitution,it can only undergo if it is substituted with an electron withdrawing group
Acetamide is a much weaker base compared to methylamine. This is due to the electron withdrawing effect of the CO group, which makes the lone pair of electrons on the nitrogen atom less available for protonation.
three dimensional arrangement of atoms electron-group geometry
The alkali metals in group 1 react by losing one electron.
it's electron-withdrawing group.
the halogens are electron withdrawing groups. e.g. F, Cl, etc
If the base hydrolysis mechanism is important, an electron withdrawing group can be attached to the prodrug. If the acid hydrolysis mechanism is important, an electron donating group can be attacked to the prodrug.
because electron-withdrawing group on side chain
yes it is
Hi ,As you know from the structures of both the compounds that toluene has a methyl group on the benzene ring which is electron releasing group and hence activate the benzene ring by pushing the elctrons on the benzene ring. On the other hand nitro group on the benzene ring is electron withdrawing group which deactivates the benzene ring by withdrawing the electrons from the benzene ring . Now in the nitration attack of the nucleophile ( NO2 +) takes place. Hence reaction will takes place on that benzene faster which have more electron density on its ring which is the case of toluene.
"OH" group attached to aromatic ring is electrons donor because it has two lone pairs of electrons on oxygen atom which may involve in resonance process, but "OH" group attached to saturated carbon act as electrons attracting group due to high electronegativity of oxygen.
An electron withdrawing group can be added at position 6 of the bicyclic system. Its inductive effects can reduce nucleophilicity.
Yes. due to the presence of electron withdrawing iodo group, iodoacetic acid will be stronger than acetic acid.
Assuming the groups are conjugated to the acid/base groups: An acid wants to lose a proton. When it loses a proton, you form an anion (or a neutral molecule, but when talking about electron donating/withdrawing groups, you assume there is a charge). The more stable the anion, the more easily the proton comes off, and the more acidic it is. A base is the opposite. A base gains a proton to become cationic. The more stable the cation, the more likely it is to pick up a proton, and the more basic it is. An electron withdrawing group can stabilize an anion (and thus make something more acidic) and an electron donating group can stabilze a cation (and make something more basic). The opposites also hold true: an electron donating group can destabilize an anion and make something less acidic, and vice versa for bases.
Fluorine's bonds are technically covalent, but it is such a strongly electron withdrawing group that for all intents and purposes its bonds can be considered ionic.
aniline is more acidic because in aniline a electron withdrawing benzene is connected.electron withdrawing capacity of benzene is due to its delocalizing pi electrons cloud.due the action of benzene the presence of unshared pair of electron over nitrogen is somehow decreases.which increases its acidic nature. But in case of ammonia there is no electron withdrawing group.so its unshared pair of electron remains undistrubed,which decreases its acidity and increases its basisity